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3 years ago

Heat is being transferred from the ground to the air above it by conduction. Explain how this is possible.

Chemistry

2 answers:

tiny-mole [99]3 years ago

7 0

Hope this help enjoy ya day

Klio2033 [76]3 years ago

4 0

Answer:

Conduction directly affects air temperature only a few centimeters into the atmosphere. During the day, sunlight heats the ground, which in turn heats the air directly above it via conduction. At night, the ground cools and the heat flows from the warmer air directly above to the cooler ground via conduction.

Explanation:

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Mixtures of benzene and cyclohexane exhibit ideal behavior. A solution was created containing 1.5 moles of liquid benzene and 2.

goblinko [34]

Answer:

Vapour pressure of cyclohexane at 50°C is 490torr

Vapour pressure of benzene at 50°C is 90torr

Explanation:

Using Raoult's law, pressure of a solution is defined by the sum of the product sbetween mole fraction of both solvents and pressure of pure solvents.

$P_{solution} = X_{A}P^0_{A}+X_{B}P^0_{B}$

In the first solution:

$X_{cyclohexane}=\frac{2.5mol}{2.5mol+1.5mol} =0.625$

$X_{benzene}=\frac{1.5mol}{2.5mol+1.5mol} =0.375$

$340torr = 0.625P^0_{A}+0.375P^0_{B}$ (1)

For the second equation:

$X_{cyclohexane}=\frac{3.5mol}{3.5mol+1.5mol} =0.700$

$X_{benzene}=\frac{1.5mol}{3.5mol+1.5mol} =0.300$

$370torr = 0.700P^0_{A}+0.300P^0_{B}$ (2)

Replacing (2) in (1):

$340torr = 0.625P^0_{A}+0.375(1233.3-2.333P^0_{A})$

$340torr = 0.625P^0_{A}+462.5-0.875P^0_{A}$

-122.5torr = -0.250P°A

$P^0_{A} = 490 torr$

Vapour pressure of cyclohexane at 50°C is 490torr

And for benzene:

$370torr = 0.700*490torr+0.300P^0_{B}$

$P^0_{B}=90torr$

Vapour pressure of benzene at 50°C is 90torr

3 0

3 years ago

Choose all of the options that demonstrate how humans are impacting the water cycle.

Fantom [35]

Answer:

A.) Air pollutants wash onto land and water bodies from precipitation

C.) Storm water runoff carries pollution

I hope I helped! ^-^

5 0

2 years ago

How many moles are in 109 grams of kf

lions [1.4K]

Answer:

Explanation:

Molar mass of KF= 39 + 19= 58g/mol

Mass of KF = 109g

Amount = mass/molar mass

Amount = 109/58

Amount = 1.9moles

4 0

3 years ago

What is a feed back loop?

Agata [3.3K]

Answer:A feedback loop is a process in which the outputs of a system are circled back and used as inputs. In business, this refers to the process of using customer or employee feedback (the outputs of a service or product), to create a better product or workplace

Explanation: Becuz ur mom

8 0

3 years ago

How mant liters at STP are in 0.575 moles of Kr

gizmo_the_mogwai [7]

Answer:

12.9 L Kr

General Formulas and Concepts:

Chemistry - Gas Laws

Using Dimensional Analysis
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Explanation:

Step 1: Define

0.575 mol Kr

Step 2: Identify Conversions

1 mol= 22.4 L at STP

Step 3: Convert

$0.575 \ mol \ Kr(\frac{22.4 \ L \ Kr}{1 \ mol \ Kr} )$ = 12.88 L Kr

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

12.88 L Kr ≈ 12.9 L Kr

8 0

3 years ago