Answer:
You have to remember this memory aid, diagonals and all.
You have to keep a tight tally of the electrons you’ve used so far so you don’t go over the number of electrons in the element you’re working on.
You have to remember how many electrons fit into each subshell (s, p, d, f).
It takes a lot of time, especially when the element has more than 20 electrons.
Explanation:
Answer:
The answer to your question is Aluminum
Explanation:
We need to warm from 22°C to 85°C
a) 45 g of water
b) 200 g of aluminum Cp = 0.905 J/cal°C
a) Water
Q = mCpΔT
Q = (45)(1)(85 - 22) = 45(63) = 2835 cal
b) Aluminum
Q = (200)(0.905)(85 - 22) = 114030 cal
To determine the number of moles(n) of a substance, divide its amount given in grams by the molar mass. The element in the problem is gold (Au) which has a molar mass of 196.97 grams per mole. The division is better illustrated below
n = 35.12 g / 196.97 grams per mole
The answer to the operation above is 0.1783 moles. Therefore, there are approximately 0.1783 moles of Au in 35.12 grams.
During the light independent reaction, carbon dioxide is fixed by adding it to a <span>5-carbon compound</span>
PH = -log [H+]
pH = -log (1.0x10^-4) = -(-4) = 4 or A
