Answer: 633.6 g of 
can be produced from the decomposition of 4.8 moles of 
Explanation:
The balanced chemical equation for decomposition of 
is :
According to stoichiometry :
1 mole of produce = 3 moles of
Thus 4.8 moles of will rproduce=
of
Mass of 
Thus 633.6 g of can be produced from the decomposition of 4.8 moles of
The percent yield of this reaction is calculated as follows
Mg3N2 + 3H2O =2NH3 + 3Mgo
calculate the theoretical yield,
moles=mass/molar mass
moles Mg3N2= 3.82 g/100g/mol= 0.0382 moles(limiting regent)
moles of H2o= 7.73g/18g/mol = 0.429 moles ( in excess_)
by use of mole ratio between Mg3N2 to MgO which is 1:3 the moles of MgO = 0.0382 x3 = 0.1146 moles
mass =moles x molar mass
the theoretical mass is therefore = 0.1146mole x 40 g/mol = 4.58 grams
The % yield = actual mass/theoretical mass x1000
= 3.60/4.584 x100= 78.5%
Answer:
D) The electrons move around the nucleus in an electron cloud
Explanation:
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