All categories

3 years ago

I need work shown as well

Mathematics

1 answer:

Hitman42 [59]3 years ago

3 0

The approximate area would be 49.6

You might be interested in

Write this equation in vertex form. y = x^2 -12x +20

kotegsom [21]

Answer:

$y = (x-6) ^ 2 -16$

Step-by-step explanation:

The vertex form for a quadratic equation has the following form:

$y = (x-h) ^ 2 + k$

Where the vertice of the equation is the point (h, k)

To transform the equation $y = x ^ 2 -12x +20$ in its vertex forms we must find its vertex.

Be a quadratic equation of the form:

$ax ^ 2 + bx + c$

Where a, b and c are real numbers, then the vertex of the equation will be:

$x = - \frac{b}{2a}$

For the given equation:

$b = -12\\a = 1$

Therefore the vertice is:

$x = - \frac{-12}{2(1)}\\\\x = 6$

Now we substitute x = 6 into the equation and find the value of k.

$y = (6) ^ 2 -12 (6) +20\\\\y = -16 = k$

Therefore the vertice is: (6, -16)

And the equation is:

$y = (x-6) ^ 2 -16$

8 0

3 years ago

Read 2 more answers

10 x 200 is how many tens

melisa1 [442]

10 x 200 is 2000
therefore there are 200 tens .

7 0

3 years ago

Read 2 more answers

Show Work Find the slope (5,-3), (-7,0)

Alex777 [14]

You'd use the equation y2-y1/x2-x1

0-(-3)/-7-5 = 3/-12 = -1/4

So -1/4 would be the slope
m= -1/4

4 0

4 years ago

Part A

Anuta_ua [19.1K]

Answer:

Part A: There are 4 zeros of the polynomial function f(x)

Part B: The zeroes of the polynomial function f(x) are -4, -1, 0, 2 ⇒ C

Step-by-step explanation:

The zeroes of a function are the x-coordinates of the point of intersection between the graph of the function and the x-axis (x-intercepts) which means values of x at y = 0

Part A:

In the given graph

∵ The graph of the function f(x) = - $x^{4}$ - 3x³ + 6x² + 8x intersects the x-axis

at 4 points

→ That means there are 4 values of x have y = 0

∴ The number of zeroes of the function is 4

∴ There are 4 zeros of the polynomial function f(x)

Part B:

∵ The graph intersects the x-axis at points (-4, 0), (-1, 0), (0, 0), (2, 0)

→ That means the values of x at y = 0 are -4, -1, 0, 2

∴ f(x) = 0 at x = -4, -1, 0, 2

∴ The zeroes of the polynomial function f(x) are -4, -1, 0, 2

4 0

3 years ago

What is the value of x?

Lubov Fominskaja [6]

It might be 64 but I’m not entirely sure on that.

8 0

3 years ago