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jeyben [28]
3 years ago
5

I need help with this please. :) thanks

Mathematics
1 answer:
IgorC [24]3 years ago
8 0

Answer:

d.  V = π(x^3 + 90x^2 + 2,400x  + 20,000)

Step-by-step explanation:

volume of cylinder = πr^2h

We have r = x + 20; h = x + 50

V = π(x + 20)^2(x + 50)

V = π(x^2 + 40x + 400)(x + 50)

V = π(x^3 + 50x^2 + 40x^2 + 2000x + 400x + 20,000)

V = π(x^3 + 90x^2 + 2,400x  + 20,000)

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The 60 visitor will get the calendar and a book.
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How many minutes have elapsed between 7:22 pm and 7:36 pm?
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The hour has stayed the same. 36-22 is 14. That's 14 minutes between.
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Clark Heter is an industrial engineer at Lyons Products. He would like to determine whether there are more units produced on the
Alborosie

Answer:

Step-by-step explanation:

Let the subscripts d and n represent day and night respectively

The null hypothesis is

H0 : μd ≥ μn

The alternative hypothesis is

H1 : μd < μn

it is a one-tailed and also a right left test because of the greater than symbol in the alternative hypothesis.

The decision rule is to reject H0: μd ≥ μn If 0.10 > p value

Since the population standard deviations are known, we would use the formula to determine the test statistic(z score)

z = (xd - xn)/√σd²/nd + σn²/nn

Where

xd and xn represents sample means for day and night respectively.

σd and σn represents population standard deviations for day and night respectively.

nd and nn represents number of samples

From the information given,

xd = 334

xn = 341

σd = 23

σ2 = 28

nd = 60

nn = 68

z = (334 - 341)/√23²/60 + 28²/68

= - 7/√20.34607843138

z = - 1.55

From the normal distribution table, the probability value corresponding to the z score is 0.061

Since the level of significance, 0.1 > 0.061, we would reject H0

Therefore, there is enough evidence to conclude that there are more units produced on the night shift than on the day shift.

8 0
3 years ago
Find the critical numbers of the function. (Enter your answers as a comma-separated list. Use n to denote any arbitrary integer
lyudmila [28]

If

f(\theta)=10\cos\theta+5\sin^2\theta

then the derivative is

f'(\theta)=-10\sin\theta+10\sin\theta\cos\theta

Critical points occur where f'(\theta)=0. This happens for

-10\sin\theta+10\sin\theta\cos\theta=0

-10\sin\theta(1-\cos\theta)=0

\implies-10\sin\theta=0\text{ or }1-\cos\theta=0

In the first case, we find

-10\sin\theta=0\implies\sin\theta=0\implies\theta=n\pi

In the second,

1-\cos\theta=0\implies\cos\theta=1\implies\theta=2n\pi

So all the critical points occur at multiples of \pi, or n\pi. (This includes all the even multiples of \pi.)

3 0
3 years ago
A circular plate has circumference 21.4 inches. What is the area of this​ plate? Use 3.14 for pi.
Brut [27]

Answer:

The area of this plate is 36.31\ \text{inches}^2.

Step-by-step explanation:

We have,

Circumference of a circular plate, C = 21.4 inches

The circumference of a circular shape is given by :

C=2\pi r

r is radius of circular shape

r=\dfrac{C}{2\pi}\\\\r=\dfrac{21.4}{2\times 3.14}\\\\r=3.4\ \text{inches}

Area of this plate is given by :

A=\pi r^2\\\\A=\pi (3.4)^2\\\\A=36.31\ \text{inches}^2

So, the area of this plate is 36.31\ \text{inches}^2.

8 0
3 years ago
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