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3 years ago

I need help with this please. :) thanks

Mathematics

1 answer:

IgorC [24]3 years ago

8 0

Answer:

d. V = π(x^3 + 90x^2 + 2,400x + 20,000)

Step-by-step explanation:

volume of cylinder = πr^2h

We have r = x + 20; h = x + 50

V = π(x + 20)^2(x + 50)

V = π(x^2 + 40x + 400)(x + 50)

V = π(x^3 + 50x^2 + 40x^2 + 2000x + 400x + 20,000)

V = π(x^3 + 90x^2 + 2,400x + 20,000)

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Akimi4 [234]

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3 years ago

What is the name of the period that has 913 in the number 913,256

Lana71 [14]

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3 years ago

Please Help!!! Determine the range of the following graph:

ELEN [110]

Answer:

[-1, 6)

General Formulas and Concepts:

Algebra I

Reading a coordinate plane

Algebra II

Range is the set of y-values that are outputted by function f(x)
Interval Notation - [Brackets] denote inclusion and (Parenthesis) denote exclusion

Step-by-step explanation:

According to the graph, our y-values span from -1 to 6. Since -1 is a closed dot, it is inclusive. Since 6 is an open dot, it is exclusive:

Range would then be [-1, 6).

5 0

3 years ago

What is the length of the shadow cast by a 12-foot lamp post when the angle of elevation of the sun is 60º? (to the nearest tent

elena-s [515]

Answer:

6.9 foot.

Step-by-step explanation:

Given: Length of lamp post= 12-foot.

The angle of elevation of the sun is 60°.

∴ The length of Lamp post, which is opposite is 12-foot.

Now, finding the length of shadow cast by foot lamp.

Length of shadow is adjacent.

∴ We know the formula for $Tan\theta$ = $\frac{Opposite}{adjacent}$

Next, putting the value in the formula.

⇒ $Tan 60° = \frac{12}{adjacent}$

Cross multiplying both side and using the value of Tan 60°

∴ Adjacent= $\frac{12}{\sqrt{3} } = 6.92$ ≅ 6.9 (nearest tenth value)

6.9 is the length of shadow cast by a 12-foot lamp post.

3 0

2 years ago

A line passes through the point (2, 10) and has a y-intercept of 4. What is the equation of the line?

KatRina [158]

Answer:

$y=3x+4$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is equal to 0)

1) Determine the slope (m)

$m=\frac{y_2-y_1}{x_2-x_1}$ where two points that the line passes through are $(x_1,y_1)$ and $(x_2,y_2)$

We're given the point (2,10) and the y-intercept of 4. Recall that the y-intercept occurs when x is equal to 0. This means that the y-intercept occurs at (0,4), giving us our second point.

Plug these points into the equation

$=\frac{10-4}{2-0}\\=\frac{6}{2}\\=3$

Therefore, the slope of the line is 3. Plug this into $y=mx+b$

$y=3x+b$

2) Determine the y-intercept (b)

The y-intercept is given; it is 4. Plug this back into $y=3x+b$

$y=3x+4$

I hope this helps!

3 0

3 years ago