3.815 that's the awnser......................................
Answer:
I cant see the picture but
heeeerrrrreeeee
LAw of conservation of Energy is an important concept to solve this problem. The energy released is equal to the energy absorbed.
Ice undergoes latent heat. MEaning there is a change in phase but not temperature and the energy is solved by (enthalpy of fusion)(mass) = 333.5J/g)(8.5g). =2834.75J.
This is equal to the energy released by the water. The energy is computed by (mass)(specific heat of water)(temperature change) = (255g)(4.16J/gK)(T)
Final equation is:
2834.75 = 255(4.16)(T)
T = 2.67K
Answer:
B.) As a medium star
Explanation:
A.) is incorrect. It is not a giant star because there a millions are stars which are much more massive.
B.) is correct. Our Sun has a radius of about 437,000 miles. Technically our Sun is classified as a G-type main-sequence star, aka. yellow dwarf star. The Sun is generally classified as this type of star.
C.) is incorrect. While the Sun's light is similar to the light of white dwarf, it is still most certainly classified as a yellow dwarf star.
D.) is incorrect. Neutrons stars are collapsed, incredibly dense stars. They are around the size of a city.