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Mars2501 [29]
3 years ago
10

1.

Chemistry
1 answer:
Serhud [2]3 years ago
3 0

Explanation:

Given that,

The frequency of electromagnetic spectrum is 2.73\times 10^{16}\ Hz

(A) Let the wavelength of this radiation is \lambda. We know that,

c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{2.73\times 10^{16}}\\\\\lambda=1.09\times 10^{-8}\ m

So, the wavelength of this radiation is 1.09\times 10^{-8}\ m.

(B) Let E is the energy associated with this radiation. Energy of an electromagnetic radiation is given by :

E=hf

h is Planck's constant

E=6.63\times 10^{-34}\times 2.73\times 10^{16}\\\\E=1.8\times 10^{-17}\ J

1 kcal = 4184 J

It means,

1.8\times 10^{-17}\ J=\dfrac{1}{4184}\times 1.8\times 10^{-17}\\\\=4.3\times 10^{-21}\ \text{kcal}

Hence, this is the required solution.

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