The minimum mass of Zinc, Zn that needs to be added to 0.500 g of iodine so that the iodine fully reacts is 0.128 g
<h3>Balanced equation </h3>
Zn + I₂ —> ZnI₂
Molar mass of Zn = 65 g/mol
Mass of Zn from the balanced equation = 1 × 65 = 65 g
Molar mass of I₂ = 127 × 2 = 254 g/mol
Mass of I₂ from the balanced equation = 1 254 = 254 g
SUMMARY
From the balanced equation above,
254 g of I₂ required 65 g of Zn
<h3>How to determine the mass of Zn needed </h3>
From the balanced equation above,
254 g of I₂ required 65 g of Zn
Therefore,
0.5 g of I₂ will require = (0.5 × 65) / 254 = 0.128 g of Zn
Thus, the minimum mass of Zn required is 0.128 g
Learn more about stoichiometry:
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