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poizon [28]
3 years ago
11

The progress of the reaction:

Chemistry
1 answer:
Blababa [14]3 years ago
6 0

Answer:

The Equilibrium constant K is far greater than 1; K>>1

Explanation:

The equilibrium constant, K, for any given reaction at equilibrium, is defined as the ratio of the concentration of the products raised to their stoichiometric coefficients divided by the concentration of reactants raised to their stoichiometric coefficients.

It tells us more about how how bigger or smaller the concentration of products is to that of the reactants when a reaction attains equilibrium. From the given data, as the color of the reactant mixture (Br2 is reddish-brown, and H2 is colourless) fades, more of the colorless product (HBr is colorless) is being formed as the reaction approaches equilibrium. This indicates yhat the concentration of products becomes relatively higher than that of the reactants as the reaction progresses towards equilibrium, the equilibrium constant K, must be greater than 1 therefore.

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Due to high evaporation rate and low precipitation, the oceanographer to find the highest salinity at the tropics.

<h3>What is salinity?</h3>

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2 years ago
If a container contains 3.5 moles and has a volume of 1.5 L, then what volume is it when it contains 8 moles? *
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8 0
3 years ago
You need to prepare 250.0 mL of a 1.35 M HCl solution from a 2.00 M HCl stock solution.
Lyrx [107]

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a. C. volumetric flask

b. B. Measure out x mL using a volumetric pipet

c. 168.75mL

d. B. Add the correct amount of stock solution then fill to the 250 mL mark with water.

Explanation:

  • The volumetric flask is mainly used in analytical chemistry to contain standard solutions or to prepare dilutions of a certain concentration of a reagent.
  • The volumetric pipette is used to deliver a given volume with greater precision and accuracy.
  • To make a dilution, the formula C1*V1 = C2*V2 is used where C is the concentration of the solution, in this case of molarity. V is the volume of the solution in ml and terms 1 and 2 correspond to the concentrated and diluted solutions respectively.

V2=\frac{1.35M*250mL}{2.00M} =168.75mL

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