Answer:
molar mass of methane CH4
= C + 4 H
= 12.0 + 4 x 1.008
= 12.0 + 4.032
= 16.042g/mol
7.31 x 10^25 molecules x 1 mole CH4 = 121.43 moles
6.02 x 10^23 CH4 molecules
121.43 moles CH4 are present.
Explanation:
not to certain if this is right or not.. but hope it helps!
Answer:
Mass of sea food = 30.98 Kg
Mass of sea food in pound = 68.31 lbs
Explanation:
Salmon, crab and oysters all are sea food.
Mass of sea food = Mass of salmon + Mass of crab + mass of oyster
Mass of salmon = 22 kg
Mass of crab = 5.5 kg
Mass of oysters = 3.48 kg
Mass of sea food = Mass of salmon + Mass of crab + mass of oyster
= 22 + 5.5 + 3.48
= 30.98 Kg
1 Kg = 2.205 lbs
Therefore, 30.98 kg = 30.98 × 2.205
= 68.31 lbs
Answer:
In order to balance the chemical equation, you need to make sure the number of atoms of each element on the reactants side is equal to the number of atoms of each element on the product side. In order make both sides equal, you will need to multiply the number of atoms in each element until both sides are equal.
Hope this helped you.
Answer: The mass of 
and 
produced are 336.6 g and 183.6 g respectively.
Explanation:
The combustion reaction between propane and oxygen leads to formation of carbon dioxide and water.
Law of Conservation of mass states that the mass will remain constant for a balanced equation. This is carried out when the total number of atoms on reactant side is same as the total number of atoms on the product side. Thus the equation must be balanced.
a) 1 mol of propane produces = 3 moles of
Thus 2.55 mol of propane produces = ![\frac{3}{1}\times 2.55=7.65 moles of [tex]CO_2](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B1%7D%5Ctimes%202.55%3D7.65%20moles%20of%20%5Btex%5DCO_2)
mass of 
b) 1 mol of propane produces = 4 moles of
Thus 2.55 mol of propane produces = ![\frac{4}{1}\times 2.55=10.2 moles of [tex]H_2O](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B1%7D%5Ctimes%202.55%3D10.2%20moles%20of%20%5Btex%5DH_2O)
mass of 
The mass of and produced are 336.6 g and 183.6 g respectively.
