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BaLLatris [955]
3 years ago
13

calculatorn the past, many students have listed that the accidental addition of too much acetic acid contributed greatly to the

di:erence between the experimental value and the accepted value. Suppose that Student A was supposed to make a 0.18 Msolution by diluting 9.0 mL of 2.0 M acetic acid to 100.0 mL. The expected pH for this solution is 2.74. The Ka of acetic acid is 1.8 x 10-5. a. What would be the expected pH if a Student A accidentally diluted 9.1 mL (instead of 9.0 mL) of the acid to 100 mL.
Chemistry
1 answer:
Tresset [83]3 years ago
6 0
Is that supposed to be a paragraph
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Answer:

Fe(CN)₂,  FeCO₃,  Pb(CN)₄,  Pb(CO₃)₂

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) Fe(CN)₂
-----> Fe²⁺ and CN⁻

-----> +2 + (-1) + (-1) = 0

2.) FeCO₃

-----> Fe²⁺ and CO₃²⁻

-----> +2 + (-2) = 0

3.)  Pb(CN)₄

-----> Pb⁴⁺ and CN⁻

-----> +4 + (-1) + (-1) + (-1) + (-1) = 0

4.) Pb(CO₃)₂

-----> Pb⁴⁺ and CO₃²⁻

-----> +4 +(-2) + (-2) = 0

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Answer:

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