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BaLLatris [955]
3 years ago
13

calculatorn the past, many students have listed that the accidental addition of too much acetic acid contributed greatly to the

di:erence between the experimental value and the accepted value. Suppose that Student A was supposed to make a 0.18 Msolution by diluting 9.0 mL of 2.0 M acetic acid to 100.0 mL. The expected pH for this solution is 2.74. The Ka of acetic acid is 1.8 x 10-5. a. What would be the expected pH if a Student A accidentally diluted 9.1 mL (instead of 9.0 mL) of the acid to 100 mL.
Chemistry
1 answer:
Tresset [83]3 years ago
6 0
Is that supposed to be a paragraph
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What is an open-loop system?
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A.  A group of related objects that do not send out or receive feedback and cannot modify themselves

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5 0
3 years ago
An unknown liquid is composed of 34.31% c, 5.28% h, and 60.41% i. The molecular weight is 210.06 amu. What is the molecular form
ozzi

In an unknown liquid, the percentage composition with respect to carbon, hydrogen and iodine is 34.31%, 5.28% and 60.41% respectively.

Let the mass of liquid be 100 g thus, mass of carbon, hydrogen and oxygen will be 34.31 g, 5.28 g and 60.41 g respectively.

To calculate molecular formula of compound, convert mass into number of moles as follows:

n=\frac{m}{M}

Molar mass of carbon, hydrogen and iodine is 12 g/mol, 1 g/mol and 126.90 g/mol.

Taking the ratio:

C:H:I=n_{C}:n_{H}:n_{I}

Putting the values,

C:H:I=\frac{34.31 g}{12 g/mol}:\frac{5.28 g}{1 g/mol}:\frac{60.41 g}{126.90 g/mol}=6:11:1

Thus, molecular formula of compound will be C_{6}H_{11}I.

4 0
3 years ago
12) _Na+ _H2O → ___ NaOH + __H2
TEA [102]

Answer:

Explanation:

2 Na+ 2 H2O →  2 NaOH + 1 H2

4 0
3 years ago
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