Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
Answer:
a) en cuántas filas la suma es igual?
2+7+2+0+2=13
0+1+6+1+0=8
2+0+2+8+1=13
es igual en dos filas la primera y la última
b)en cuántas columnas la suma es igual?
2+0+2=4
7+1+0=8
2+6+2=8
0+1+8=9
2+0+1=3
es igual en dos columnas la segunda y la tercera
listo :)
Step-by-step explanation:
The answer is c! you just subtract: 3/2-1/2, which is 1.
Answer:
2,592 square cm.
Step-by-step explanation:
It is given that the dimensions of rectangle A are four times the dimensions of rectangle B.
Let dimensions of rectangle B are l×b.
So, the dimensions of rectangle A are 4l×4b.
Area of rectangle is
Area of rectangle B is
The area of rectangle B is 162 square cm.
Area of rectangle A is
Therefore, the area of rectangle A is 2,592 square cm.
Answer:
7/2
Step-by-step explanation:
(3,2) (5,9): Slope -->
(9-2)/(5-3) = 7/2
