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ikadub [295]
3 years ago
8

Why is the graph of the rose curve r=4cos2theta

Mathematics
1 answer:
grandymaker [24]3 years ago
8 0

Answer:

The correct answer is B.

Step-by-step explanation:

Any point can be represented in polar form by using the notation:

A = (r, \theta) (1)

And any polar function must satisfy the following definition:

r = f(\theta)

Let r(\theta) = 4\cdot \cos 2\theta, where r is the radial distance of any point of the curve from origin and \theta is the direction of any point of the curve with respect to +x semiaxis, measured in radians.

Finally, we proceed to graph the function with the help of a graphing tool and attach the result.

Besides, we must remember that cosine is a bounded function, which means that domain and range in rectangular coordinates are represented by:

Dom\{f\} = [-4,4], Ran\{f\} = [-4,4]

Then, the correct answer is B.

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Determine the amplitude (A), period (P), and phase shift (PS) of the function f(x)= 3sin(x-4)+9
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