Answer:
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Answer:
2.54 seconds
Step-by-step explanation:
We can use the following equation to model the vertical position of the ball:
S = So + Vo*t + a*t^2/2
Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.
Then, using S = 2.5, So = 0.4, Vo = 14 and a = -9.8 m/s2, we have that:
2.5 = 0.4 + 14*t - 4.9t^2
4.9t^2 - 14t + 2.1 = 0
Solving this quadratic equation, we have that t1 = 2.6983 s and t2 = 0.1588 s.
Between these times, the ball will be higher than 2.5 m, so the amount of time the ball will be higher than 2.5 m is:
t1 - t2 = 2.6983 - 0.1588 = 2.54 seconds
Answer:
Step-by-step explanation:
1. HI // KL , J is midpoint of HL 1. Given
2. ∠IHJ ≅ ∠JLK 2. Alternate interior angles are congruent
3. ∠IJH ≅ ∠KJL 3. Vertically opposite angles
4. HJ ≅ JL 4. Given
5. ΔHIJ ≅ ΔLKJ 5. A S A congruent
(Angle Side Angle)
Okay i’m pretty sure it’s the first one, 1 square and 4 triangles.