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3 years ago

A , B, C , D probability

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

4 0

Answer:

your laptop is nice really

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Enter your answer and show all the steps that you use to solve this problem in the space provided.

Nutka1998 [239]

The factorized expression is: 2(k+5)

Step-by-step explanation:

The distributive property is used to factorize the expressions with common factors. The common factor is taken out from the expression for the purpose of simplification

Given expression is:

$2k+10$

We can see that 2 is a common factor in both terms

So,

$= 2.k + 2.5\\= 2(k+5)$

The factorized expression is: 2(k+5)

Keywords: Factorization, distributive

Learn more about polynomials at:

#LearnwithBrainly

6 0

4 years ago

Fully simplify 7hw+5wh + 3hw

Romashka-Z-Leto [24]

Answer:

15hw.

Step-by-step explanation:

Note 5wh is the same as 5hw, so we have:

7hw+5hw + 3hw

= 15hw.

Or, if you like, you could write it as 15wh.

4 0

1 year ago

Plźzzz help me ... I'll give brainliest

fgiga [73]

Answer:

$\displaystyle x = \frac{1}{3}$ .

Step-by-step explanation:

Consider the double angle identity for tangents:

$\displaystyle \tan(2\theta) = \frac{2\tan{\theta}}{1 - \tan^{2}{\theta}}$ .

Also, for two complementary angles,

$\displaystyle \tan{\left(\frac{\pi}{2} - \theta \right)} = \frac{1}{\tan{\theta}}$ .

Subtract $\tan^{-1}(x + 1)$ from both sides of this equation:

$\displaystyle 2\tan^{-1}{x} = \frac{\pi}{2} + (-\tan^{-1}(x + 1))$ .

Take the tangent of both sides of this equation:

$\displaystyle \tan(2\tan^{-1}{x}) = \tan\left(\frac{\pi}{2} -\tan^{-1}\left(x + 1\right)\right)$ .

Apply the double-angle identity to the left-hand side of this equation:

$\displaystyle \tan(2\tan^{-1}{x}) \implies \frac{2\tan(\tan^{-1}x)}{1 - \tan^{2}(\tan^{-1}x)}\implies \frac{2x}{1 - x^{2}}$ .

The two angles $\displaystyle \left(\frac{\pi}{2} + (-\tan^{-1}\left(x + 1\right))\right)$ and $(x - 1)$ are complementary. Therefore, for the right-hand side of this equation,

$\displaystyle \tan\left(\frac{\pi}{2} -\tan^{-1}\left(x + 1\right)\right)\implies \frac{1}{\tan(\tan^{-1}(x + 1))} \implies \frac{1}{x + 1}$ .

Equate the two sides of this equation:

$\begin{aligned} & \frac{2x}{1 - x^{2}} = \frac{1}{x + 1}\\ \implies & \frac{2x}{(1 - x)(1 + x)} = \frac{1}{1 + x}\\\implies & 2x = 1 - x,\; x \ne 1,\; x \ne -1\\\implies & x = \frac{1}{3}\end{aligned}$ .

5 0

3 years ago

Slope:-2;y intercept: 3

drek231 [11]

Answer:

y = -2x + 3

Step-by-step explanation:

Hope this helps!

5 0

4 years ago

Keisha runs 3 miles in 28 minutes. At the same rate, how many miles would she run in 42 minutes?

leva [86]

Around 5 but not exactly, sorry couldn't do the full thing

7 0

3 years ago