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kicyunya [14]
3 years ago
5

How do I long divide ?

Mathematics
1 answer:
katovenus [111]3 years ago
3 0
If you are dividing numbers than here are some steps. 

<span>Divide.
Multiply & subtract.
Drop down the next digit. h t o. ) 2 7 8.
Two goes into 2 one time, or 2 hundreds ÷ 2 = 1 hundred. h t o. ) 2 7 8. - ...Divide.Multiply & subtract.<span>Drop down the next digit. h t o. 1 3 9. ) 2 7 8. - 0 7. - 1 8.

Hope this helps! I used this to teach myself.</span></span>
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Mrs. Nicholas baked two batches of cookies. The first batch consisted of 120 gingerbread cookies and the second batch consisted
shusha [124]

Answer:

i think 2/15 of the cookies

Step-by-step explanation:

hope this helps

3 0
1 year ago
Find the surface area and show work
Law Incorporation [45]

Answer: 1,270in^2

Step-by-step explanation:

The surface area of a rectangle can be calculated with:

Area_{rectangle}=lenght*width

The surface area of a trapezoid can be calculated with:

Area_{trapezoid}=\frac{height}{2}(Larger\ base+Smaller\ base)

Calculate the area of the base, wich is a rectangle:

A_{1}=(34in)(15in)=510in^2

There are two equal rectangles, therefore, multiply the area of any of them by 2:

A_{2}=2(15in)(13in)=390in^2

Calculate the area of the other rectangle:

A_{3}=(15in)(10in)=150in^2

There are two equal trapezoids, therefore, multiply the area of any of them by 2:

A_4=\frac{2(5in)}{2}(34in+10in)=220in^2

Therefore, the surface area will be the sum of all the areas calculated:

SA=A_1+A_2+A_3+A_4\\\\SA=510in^2+390in^2+150in^2+220in^2\\\\SA=1,270in^2

7 0
3 years ago
Please help with geometry. 20 points, and another question worth 98 on my profile!
vovikov84 [41]

Answer:

Part 1) m∠1 =(1/2)[arc SP+arc QR]

Part 2) PR^{2} =PS*PT

Part 3) PQ=PR

Part 4) m∠QPT=(1/2)[arc QT-arc QS]

Step-by-step explanation:

Part 1)

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

we have

m∠1 -----> is the inner angle

The arcs that comprise it and its opposite are arc SP and arc QR

so

m∠1 =(1/2)[arc SP+arc QR]

Part 2)

we know that

The <u>Intersecting Secant-Tangent Theorem,</u> states that the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

so

In this problem we have that

PR^{2} =PS*PT

Part 3)

we know that

The <u>Tangent-Tangent Theorem</u>  states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments

so

In this problem

PQ=PR

Part 4)

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

In this problem

m∠QPT -----> is the outer angle

The arcs that it encompasses are arc QT and arc QS

therefore

m∠QPT=(1/2)[arc QT-arc QS]

4 0
3 years ago
I really need help. It would mean a lot ❤️!
crimeas [40]

Answer: The domain has to be x and the range y. But for independent and dependent variable I can't help. So srry. The picture doesn't show the work. Have a nice day :)

4 0
3 years ago
What are the values of x and y in the diagram?
deff fn [24]
X and y are points that help u place other points
5 0
3 years ago
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