As per the question the initial speed of the car [ u] is 42 m/s.
The car applied its brake and comes to rest after 5.5 second.
The final velocity [v] of the car will be zero.
From the equation of kinematics we know that
[ here a stands for acceleration]
Here a is taken negative as it the car is decelerating uniformly.
We are asked to calculate the stopping distance .
From equation of kinematics we know that
[here S is the distance]
![= 42*5.5 +\frac{1}{2} [-7.64] [5.5]^2 m](https://tex.z-dn.net/?f=%3D%2042%2A5.5%20%2B%5Cfrac%7B1%7D%7B2%7D%20%5B-7.64%5D%20%5B5.5%5D%5E2%20m)
[ans]
Answer:
This point is not accelerating.
Explanation:
An object can be acted on by several forces at the same time, these forces are vector quantities (with magnitude and direction associated). The vector sum of all of the forces acting on a body is a single force called the net force when an object is in equilibrium this net force is equal to zero.
<em>According to Newton's second law of motion, the acceleration of an object as produced by a net force is directly proportional to the net's force, direction, and force and inversely proportional to the mass of the object. </em><em>This means that if the net force is zero an object will have zero acceleration.</em>
Therefore we can conclude that the sum of the three forces acting on the center point of the rope is assumed to be zero this point is not accelerating.
I hope you find this information useful and interesting! Good luck!
It will land at 14139.19 m away.
Explanation:
The expression for range d on level ground is given by;
d=v² sin (2Ф) /g where Ф is the fire angle and g is acceleration due to gravity
Given v=400m/s ,Ф= 60° and g=9.8 so,
d= 400² sin(120°) /9.8
d=(400²×0.86602540378) / 9.8
d=14139.19 m
Motion for falling object : brainly.com/question/11799308
Keyword : initial velocity, angle, range
#LearnwithBrainly
Answer:
The answer to your question is: 5 N to the west or to the left
Explanation:
Both forces go to the left, so the net force will be the sum of them.
Net force = 3 N + 2 N
Net force = 5 N
to the left, because the arrows signal to that direction
The best estimate of the orbital period of a typical asteroid is 9.0 earth years.
