The magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.
<h3>What is the magnitude of electrical forces between two charges?</h3>
The magnitude of the electrical force between two charges refers to the attractive or repulsive forces that exists between two charges separated by a given distance in an electric field.
The magnitude of the electrical force, F between the two charges q2 and q3 is given be my the formula below

Therefore, the magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.
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The volume of a cube is given by:

where L is the measure of each side (which corresponds to its width, since all sides of a cube are equal).
Plugging the data of the problem, L=32.1 cm, inside the equation, we find the volume:

10+8 = 18
5+2 = 7
18-7 = 11
a) to the right by 11N.
Answer:
10 N
Explanation:
I assume there is no friction and we are only worrying about the horizontal direction. If so we use the formula F=MA to get F= 2 * 5 = 10 N
Answer:
The answer depends on the arrangement of the batteries either parallel or series.
If the three batteries are connected in parallel, the voltmeter will read the same voltage as the individual battery (I.e, the combine voltage will remain 1.5 Bolts)
While
If the batteries are connected in series, and are correctly connected together from positive to negative, the combine voltages will increase by adding individual battery voltage together. So for three 1.5 Volts batteries, the total voltages will be 4.5 Volts.
Explanation:
Parallel connected
Vp = 1.5 Volts
Series connection
Vs = 1.5 + 1.5 + 1.5 = 4.5Volts