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makkiz [27]
3 years ago
12

Earth’s atmosphere is in hydrostatic equilibrium. What this means is that the pressure at any point in the atmosphere must be hi

gh enough to support the weight of air above it. How would you expect the pressure on Mt. Everest to differ from the pressure in your classroom? Explain why.
Physics
1 answer:
Misha Larkins [42]3 years ago
6 0

Answer: The pressure that one experiences on the Mount Everest will be different from the one, in a classroom. It is because pressure and height are inversely proportional to each other. This means that as we move up, the height keeps on increasing but the pressure will keep on decreasing. This is the case that will be observed when one stands on the Mount Everest as the pressure is comparatively much lower there.

It is because as we move up, the amount of air molecules keeps on decreasing but all of the air molecules are concentrated on the lower part of the atmosphere or on the earth's surface.

Thus a person in a low altitude inside a classroom will experience high pressure and a person standing on the Mount Everest will experience low pressure.

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A hard-boiled egg of mass 46.0 gg moves on the end of a spring with force constant 25.6 N/mN/m . The egg is released from rest a
soldi70 [24.7K]

Answer:

0.022kg/s

Explanation:

We are given that

Mass of boiled egg=46 g=\frac{46}{1000} kg=0.046 kg

1kg=1000 g

Constant force=F=25.6 N/m

Initial displacement=A_1=0.296 m

Final displacement=A_2=0.12 m

Time=t=4.55 s

Damping force=F_x=-bv_x

We have to find the  magnitude of damping constant b.

We know that the displacement of the oscillator under damping motion is given by

x=Ae^{-\frac{b}{2m}t}cos(w't+\phi)

For maximum displacement cos(w't+\phi)=1

Therefore , x=A_2

Substitute the values

A_2=A_1e^{-\frac{-b}{2m}t}

e^{-\frac{b}{2m}t}=\frac{A_2}{A_1}

-\frac{b}{2m}t=ln\frac{A_2}{A_1}

lnx=y\implies x=e^y

Substitute the values

-\frac{b}{2\times 0.046}\times 4.55=ln\frac{0.12}{0.296}

\frac{2\times 0.046}{4.55b}=ln\frac{0.296}{0.12}

\frac{2\times 0.046}{4.55}=0.9b

b=\frac{2\times 0.46}{4.55\times 0.9}=0.022kg/s

Hence,the  magnitude of damping constant b=0.022kg/s

3 0
2 years ago
In photography what are clouds best described as?
Dima020 [189]

Answer:

gas

Explanation:

6 0
3 years ago
Hurricanes are considered____ because they lose power over cool waters or land A. Short-lived B. Heat engines C. Weak
klasskru [66]
My best guess would be heat engines
7 0
3 years ago
Read 2 more answers
How can an object overcome static friction?
larisa86 [58]

Answer:

Applying enough force in one direction to move the object, making kinetic energy.

Explanation:

Simpleness

4 0
2 years ago
Are the units of the formula ma = mv2/2 dimensionally consistent? Select the single best answer.
Vesnalui [34]

To solve the problem we will simply perform equivalence between both expressions. We will proceed to place your units and develop your internal operations in case there is any. From there we will compare and look at its consistency

ma = \text{Mass}\times \text{Acceleration}

ma = kg \cdot \frac{m}{s^2}

At the same time we have that

\frac{1}{2}mv^2 = \text{Mass}\times \text{Velocity}^2

\frac{1}{2}mv^2 = kg ( \frac{m}{s})^2

\frac{1}{2}mv^2 = kg \cdot \frac{m^2}{s^2}

Therefore there is not have same units and both are not consistent and the correct answer is B.

5 0
3 years ago
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