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3 years ago

I need the question answers

Mathematics

1 answer:

jonny [76]3 years ago

6 0

5. mitosis
6. sex cells
7. two daughter cells
8. not sure. . . reproduction
9. also reproduction?

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Translate the sentence into an equation. The sum of 3 times a number and 7 is 19.

klemol [59]

D. Because you're multiplying 3 by a number which is what the variable represents (n), then you're just adding 7 to that which equals 19 all together. It all translates to 3n+7=19.

7 0

3 years ago

While completing a multiplication problem I need to know how to do it by associative

Vera_Pavlovna [14]

Associative property Says that you can add or multiply regardless of how the numbers are group

3 0

3 years ago

Please please help please

RideAnS [48]

Answer: 72 feet

Step-by-step explanation:

24 yards= 72 feet

8 0

2 years ago

Read 2 more answers

Luis hizo un viaje en el coche en el cual consumio 20 l de gasolina. el trayecto lo hizo en dos etapas en la primera consumio 2/

algol13

Answer: $24\ liters$

Step-by-step explanation:

Let be "x" the amount of gasoline in liters that the car's tank had at the beginning of the trip.

1. In the first part of the trip the amount of gasoline the car used can be expressed as:

$\frac{2}{3}x$

2. After the first part of the trip, the remaining was:

$x-\frac{2}{3}x=\frac{1}{3}x$

3. In the second part of the trip the car used $\frac{1}{2}$ of the remaining. This is:

$(\frac{1}{3}x)(\frac{1}{2})=\frac{1}{6}x$

4. The total amount ot gasoline used in this trip was 20 liters.

5. Then, with this information, you can write the following equation:

$\frac{2}{3}x+\frac{1}{6}x=20$

6. Finally, you must solve for "x" in order to find its value. This is:

$\frac{2}{3}x+\frac{1}{6}x=20\\\\\frac{5}{6}x=20\\\\5x=120\\\\x=24$

3 0

2 years ago

Estimate 1 13 cos(x2) dx 0 using the Trapezoidal Rule and the Midpoint Rule, each with n = 4. (Round your answers to six decimal

babunello [35]

Answer:

(a) 4.152698

(b) 3.215557

Step-by-step explanation:

(a)

$\int\limits^{13}_1 {cos(x^2)} \, dx =M_n=$\sum_{n=1}^{\infty} f(m_i)\Delta x $$

n=4, so :

Each subinterval has length :

$\Delta x= \frac{b-a}{n} =\frac{13-1}{4} =\frac{12}{4} =3$

Therefore the subintervals consist of:

$[1,5], [5,9], [9,13]$

Now, the midpoints of these subintervals are:

$\frac{1+5}{2} =3\\\\\frac{5+9}{2} =7\\\\\frac{9+13}{2} =11$

Hence:

$M_4= 3*(cos(3^2))+3*(cos(7^2))+3*cos((11^2))\approx 4.152698$

(b)

$\int\limits^{13}_1 {cos(x^2)} \, dx =T_n=\frac{\Delta x}{2} (f(x_o)+2f(x_1)+2f(x_2)+...+2f(x_n_-_1)+f(x_n))$

n=4, so :

Each subinterval has length :

$\Delta x= \frac{b-a}{n} =\frac{13-1}{4} =\frac{12}{4} =3$

Therefore the subintervals consist of:

[1,5], [5,9], [9,13]

The endpoints of the subintervals consist of:

5,9

Hence:

$T_4= \frac{3}{2}(cos(1^2)+2*cos(5^2)+2*cos(9^2)+cos(13^2)) \approx 3.215557$

8 0

2 years ago