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Volgvan
3 years ago
12

4c+6+2 if anyone can tell me the answer it would mean so much!

Mathematics
2 answers:
IRISSAK [1]3 years ago
6 0
Add the like terms 6+2=8
4c is left on its on because there is no other like it

So you’re left with 4c+8
hodyreva [135]3 years ago
3 0

Answer:

Just combine like terms

6+2=8

4c can’t be combines

so 4c+8

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The formula x + y = 180 can be used to find the degrees of supplementary angles, where x is the smaller angle. Find the domain a
maks197457 [2]

Answer:

Domain : 0° < x <90°

Range: 90° < y < 180°.

Step-by-step explanation:

When we have a function:

f(x) = y

the domain is the set of the possible values of x, and the range is the set of the possible values of y.

In this case we have:

x + y = 180°

such that x < y

Let's analyze the possible values of x.

The smallest possible value of x must be larger than 0°, as we are workin with suplementary angles.

Knowing this, we can find the maximum value for y:

0° + y = 180°

y = 180° is the maximum of the range.

Then we have:

0° < x

y < 180°

To find the other extreme, we can use the other relation:

x < y.

Then, we can impose that x = y (this value will not be either in the range nor the domain)

if x = y then:

x + y = x + x = 180

2*x = 180

x = 90°

This will be the maximum of the domain and the minimum of the range.

Then we have that the domain is:

0° < x <90°

And the range is:

90° < y < 180°.

5 0
3 years ago
IN NEED OF A MATH WIZ!!!!!
densk [106]
The unoccupied volume will be the volume of the can minus the volume of the three tennis balls.

V=HπR^2-3(4πr^3)/3

V=HπR^2-4πr^3  where H=height of can, R=radius of can, r=radius of ball

We are told H=7, R=1.5, and r=1.125  (2.25/2=d/2=r) so

V=7π1.5^2-4π1.125^3

V=15.75π-5.6953125π  in^3

V≈31.58 in^3
5 0
3 years ago
Read 2 more answers
A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet
gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

h(x)=10+0.1(x^{1.5})

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}

s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx

s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx

s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx

Let 1+0.0225x=t

dx=\frac{1}{0.0225}dt

s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt

s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}

s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}

s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)

s=28.21

Weight of cable=28.21\times 10.4=293.38pound

8 0
3 years ago
Which equation could represent Relationship A?
AleksAgata [21]
Hahshddhhddbjddjdjxdjdjfj
8 0
3 years ago
Read 2 more answers
Ronnie goes to the racetrack with his buddies on a weekly basis. One week he tripled his money, but then lost $12. He took his m
Tamiku [17]

Answer:

20

Step-by-step explanation:

224÷4 = 56+40 = 96÷2 = 48+12 = 60÷3 = 20

3 0
3 years ago
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