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3 years ago

What is a cube game called

Mathematics

2 answers:

sertanlavr [38]3 years ago

7 0

A cube is called a cube

il63 [147K]3 years ago

4 0

A Game Cube is Simply called a Game Cube it can be used for sega games and many up down games it uses a box with one joy stick and two buttons it connects to your tv with a decent range of games to play although they are basic

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Find the perimeter. Can someone guide me on how to do this?

Eddi Din [679]

Just add all the way around I will start on the left and go to the right
23+5+5+8+ 5+6+23+19= 94

Got the 8 by getting the bottom line which is 19 and subtracting the two top pieces 5&6

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3 years ago

On friday 1/6 of band pracitce was spent trying on uniforms. the band spent 1/6 of practice on marching, the remaining practice

Stella [2.4K]

4/6 of the time was spent to play music because 1/6 + 1/6 = 2/6
6/6 - 2/6 = 4/6

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3 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

DaniilM [7]

A ) h = -16 t² + 135 t + 76
Let : h = 0
0 = - 16 t² + 135 t + 76
B ) t 1/2 = (-b+/- √ ( b² - 4 ac ) / ( 2 a )
t 1/2 = (-135 - √(18,225 + 4,864))/ (-32) = ( - 135 - 151.95) / (- 32)=
= (-286.95) / (- 32) = 9.967 ≈ 9.0 s ( other solution is negative )
Answer:
2) 0 = -16 t² + 135 t + 76; 9 s

7 0

3 years ago

Read 2 more answers

Everything is in the picture

Afina-wow [57]

Answer:

It's x = -1.5

Step-by-step explanation:

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2 years ago

The equation x ^ 2 - 2x + y ^ 2 - 4y = 20 defines a circle in the xy-coordinate plane What is the radius of the circle?

Helga [31]

Answer:

I'll set up the problem and you can do the calculation

Step-by-step explanation:

we need to complete the squares to get the equation in the general form:

${(x - h)}^{2} + {(y - k) }^{2} = {r}^{2}$

where h = the x coordinate of the center

k = the y coordinate of the center

r = the radius

so looking at

${x}^{2} - 2x$

we can see that if use -1 as the constant we have

${(x - 1)}^{2} = {x}^{2} - 2x + 1$

doing the same for y

${y}^{2} - 4y$

we can use -2 as the constant (basically you that the s

quare of the y coefficient )

${(y - 2)}^{2} = {y}^{2} - 4y + 4$

so now we have to add or subtract the constant on the RHS to see what the square of the radius is according to the general form of the equation at the top

20 +1+4=25

Take the square root and you have the radius

4 0

2 years ago