Answer:
18/245.
Step-by-step explanation:
Total number of coins = 12+15+23 = 50.
Prob(Karen chooses a dime) = 15/50 = 3/10.
Prob(Mikah then chooses a quarter) = 12/49. ( Karen has already removed one coin)
Prob(of Karen choosing a dime then Mikah a quarter)
= 3/10 * 12/49
= 36/490
= 18/245.
Answer:
The required number will be:
Step-by-step explanation:
Let 'x' be the number
so
23.2% of x = 34.8
23.2% × x = 34.8
23.2/100 × x = 34.8
0.232x = 34.8
divide both sides by 0.232
0.232x/0.232 = 34.8/0.232
x = 150
Therefore, the required number will be:
To find the y int, sub in 0 for x and solve for y
y = 1/3x - 6
y = 1/3(0) - 6
y = -6.....so the y int is -6 or (0,-6) <==
to find the x int, sub in 0 for y and solve for x
y = 1/3x - 6
0 = 1/3x - 6
-1/3x = -6
x = -6 / (-1/3)
x = -6 * -3
x = 18....so the x int is 18 or (18,0) <==
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Answer:
Step-by-step explanation:
There are
2 yellow
3 magenta
5 blue
marbles in the bag.
So total of 2 + 3 + 5 = 10 marbles
We have to multiply the probability of yellow on first pick by the probability of yellow on second pick (WITHOUT REPLACEMENT).
We denote P(Y1) as probability of yellow on first draw &
P(Y2) as probability of yellow on second draw
Thus,
P(Y1) = 2/10 = 1/5 [since 2 yellow and 10 total marbles]
Now,
P(Y2) = 1/9 [since now 1 yellow is taken out and NOT replaced, so we have 1 yellow remaining and total 9 marbles]
Now, we multiply:
P(Y1) * P(Y2) = 1/5 * 1/9 = 1/45
The probability is
