Please explain more :))
Oh nvm this
(4+9) + (2-1) = 12
If f(X)= 7x +5/3 - x =6x +5/3
y= 6x +5/3
6x= y-5/3
f^-1(y)=x=(y-5/3)/6
So we can write
f(f^-1(y))= f((y-5/3)/6) = 6 (y-5/3)/6 +5/3= y-5/3+5/3= y
The same result can be obtained for f^-1(f(x))=x
If the function is f(x)= 7x +5/(3-x) then it is not invertible since it is not injective (pictures)
Let
be the smaller integer. The larger integer is then
, and we have






We omit
, since
is negative.
Then for
we find
, but this is not odd.
There are no consecutive odd integers that satisfy the given condition!
<u><em>FALSE.</em></u><em></em>
A composite number is the opposite of a prime number. This is false because of the possibility of the following scenario:
The two numbers are 1 and a prime number.
This is because <em>one multiplied by any number is that number.</em> A prime number cannot become a composite number just because it is being multiplied by one. For example:
1 x 7 = 7 (prime)
Hope this helps!
~<em>Archimedes El</em>∈<em>ven</em>
Answer:
x = -1, y = -2.
Step-by-step explanation:
Using the elimination method,
multiply the first eqn by 2 and the 2nd eqn by 5.
6x - 10y = 14
25x - 10y = -5
Subtract one of the new equations from the other
-19x = 19
x = -1
Sub x=-1 into the 2nd eqn
-5 - 2y = -1
y = -2
Hence x = -1, y = -2.