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masya89 [10]
2 years ago
6

Please help if you understand this question!

Mathematics
1 answer:
Solnce55 [7]2 years ago
7 0

Answer:

B. x=5, y=4

Step-by-step explanation:

the tiny triangle is 3x smaller so just divide those numbers by three

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a baker makes cakes and sells them at county fairs his initial cost was $45 to reserve a booth and $25 traveling expenses. He fi
swat32
Sorry but I don't know this question
6 0
3 years ago
Given the coordinates below, what is the midpoint of AB?<br> A(-6, -10)<br> B(2,5)
madreJ [45]

Given :

\:

  • A(-6, -10)
  • B( 2, 5)

\:

\gray{ \frak{The \:  given \:  two \:   \: points  \: are(x_{1 },y_{1})=(−6 , -10)and(x_{ 2 },y_{2} )=( 2,5 )\:}}

\:

Let's solve by using midpoint formula :

\:

\bf \boxed{\color{red}\frak{Midpoint \:   \: Formula :  {( \: x ,\:y \:  ) = }(  \frak{ \frac{x_{1 } + y_{1}}{2} , \frac{x_{2 } + y_{2}}{2} )}}}

\:

\large \gray{ \frak{( \: x ,\:y \:  ) = }(  \frak{ \frac{ -6 + 2}{2} , \frac{ - 10 + 5}{2} )}}

\:

\: \large \gray{ \frak{( \: x ,\:y \:  ) = }(  \frak{ \frac{ -4}{2} , \frac{ - 5}{2} )}}

\:

\large \gray{ \frak{( \: x ,\:y \:  ) = }(  \frak{  \cancel\frac{ -4}{2} ,  \cancel\frac{ - 5}{2} )}}

\:  \:

\underline{ \boxed{ \large \red{ \frak{option \: d }(  \frak{   - 2, - 2.5)}}}}✓

Hope Helps! :)

6 0
2 years ago
-2y + 2x = 10 for x please help
AleksAgata [21]
-2y+2x=10
2x=10+2y
x=5+y
7 0
3 years ago
Read 2 more answers
Question 6 of 10
mamaluj [8]

Answer:

A

Step-by-step explanation:

I didn't learn jrf, but I believe that it is the amount of females that watch action movies divided by the total amount of females.

Amount of females who watch action movies= 99

Total females= 250

So, A seems correct.

4 0
2 years ago
The perimeter of a semicircle is 5.14 feet. What is the semicircle’s area?
hammer [34]
\bf \textit{circumference of a semi-circle}\\\\&#10;C=\pi r\qquad &#10;\begin{cases}&#10;r=radius\\&#10;-----\\&#10;C=5.14&#10;\end{cases}\implies 5.14=\pi r\implies \boxed{\cfrac{5.14}{\pi }=r}\\\\&#10;-------------------------------\\\\&#10;\textit{area of a semi-circle}\\\\&#10;A=\cfrac{\pi r^2}{2} \implies A=\cfrac{\pi }{2}r^2\implies A=\cfrac{\pi }{2}\left( \boxed{\cfrac{5.14}{\pi }} \right)^2&#10;\\\\\\&#10;A=\cfrac{\pi }{2}\implies \cfrac{5.14^2}{\pi ^2}\implies A=\cfrac{26.4196}{2\pi }\implies A=\cfrac{13.2098}{\pi }
5 0
2 years ago
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