Answer:a>4
Step-by-step explanation:
Since in 1990 there are 28%, we need to figure out when it gets to 31%. In addition, since it increases by 0.6% every year, we can say that 0.6x+28 (since 28 is the base value) is the percentage of babies born in wedlock every year. Therefore, to get 0.6x+28=31, we subtract 28 from both sides to get 0.6x=3
Dividing both sides by 0.6, we get x=5=the amount of years it takes to get 31% of babies born in wedlock. Since 1990 is the base value (we start from there!), we add 5 to that to get 1990+5=1995 as the yar
The answer is x >_ -2 and x >_ 7.
N+3=7. To find n, you need to have it by itself, so you can do that by subtracting 3 on both sides, so it would look like: n+3-3=7-3. Then you have n=4.
Answer:
Range of the average number of tours is between 150 and 200 including 150 and 200.
Step-by-step explanation:
Given:
The profit function is modeled as:
The profit is at least $50,000.
So, as per question:
Now, rewriting the above inequality in terms of its factors, we get:
Now,
![x0\\x>200,(x-150)(x-200)>0\\For\ 150\leq x\leq200,(x-150)(x-200)\leq 0\\\therefore x=[150,200]](https://tex.z-dn.net/?f=x%3C150%2C%28x-150%29%28x-200%29%3E0%5C%5Cx%3E200%2C%28x-150%29%28x-200%29%3E0%5C%5CFor%5C%20150%5Cleq%20x%5Cleq200%2C%28x-150%29%28x-200%29%5Cleq%200%5C%5C%5Ctherefore%20x%3D%5B150%2C200%5D)
Therefore, the range of the average number of tours he must arrange per day to earn a monthly profit of at least $50,000 is between 150 and 200 including 150 and 200.
