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mylen [45]
3 years ago
12

PLEASE HELP ASAP IT IS VERY MUCH APPRECIATED

Mathematics
2 answers:
irakobra [83]3 years ago
5 0
YOUR CORRECT good luckkk
Alika [10]3 years ago
3 0

Answer:

I think the answer is y= -2/x

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Anybody know this question
Dmitrij [34]
<h3>Answers :-</h3>
  • sinB = 12/13
  • cosB = 5/13
  • tanB = 12/5

Here as by the given information ,

♦ sinA = Opposite/Hypotenuse

♦ cosA = Adjacent/Hypotenuse

♦ TanA = Opposite/adjacent

So here we need to find the same for angle B so we need to use the same formulas for angle B also .

→ sinB = Opposite/Hypotenuse = 12/13

→ cosB = Adjacent/Hypotenuse = 5/13

→ tanB = Opposite/Adjacent = 12/5

8 0
3 years ago
Write 6 3/2 in surd form.​
dolphi86 [110]

Answer:

6\sqrt{6}

Step-by-step explanation:

Simplify using a\frac{n}{m} =\sqrt[m]{a^n} :\sqrt{6^3}

Factor and rewrite the radicand in exponential form: \sqrt{6^2 x 6}

Rewrite the expression using \sqrt[n]{ab} =\sqrt[n]{a}*\sqrt[n]{b} : \sqrt{6^2x\sqrt{6}

Simplify  the radical expression

6\sqrt{6}

6 0
2 years ago
Help desprate here.....
rjkz [21]

Answer:

B. 3

It says the answer is too short so im just typing random stuff

6 0
3 years ago
Read 2 more answers
Consider the quadratic function f(x)=−x^2+x+30
yaroslaw [1]

Answer:

The smallest xx-intercept is x = -5

The largest xx-intercept is x = 6

The yy-intercept is y = 30.

Step-by-step explanation:

Given a quadratic function in the following format:

f(x) = ax^{2} + bx + c = 0, a \neq 0

The x-values of the x-intercepts are x_{1}, x_{2}, given by the following formulas.

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

We have that:

f(x) = -x^{2} + x + 30

This is not in the format above. I will multiply by (-1), so we have:

f(x) = x^{2} - x - 30

So, a = 1, b = -1, c = -30

\bigtriangleup = b^{2} - 4ac = (-1)^{2} - 4*(1)*(-30) = 1 + 120 = 121

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) + \sqrt{121}}{2(1)} = \frac{12}{2} = 6

x_{2} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) - \sqrt{121}}{2(1)} = \frac{-10}{2} = -5

This means that

The smallest xx-intercept is x = -5

The largest xx-intercept is x = 6

The y-intercept is the value of f(x) when x = 0. So

f(x)=−x^{2}+x+30

f(0) = 30

The yy-intercept is y = 30.

5 0
3 years ago
Solve the proportion.<br><br> 2/x+3=5/x
xenn [34]

 

\displaystyle\bf\\\frac{2}{x+3}=\frac{5}{x}\\\\5(x+3)=2x\\\\5x+15=2x\\\\5x-2x=-15\\\\3x=-15\\\\x=\frac{-15}{3}\\\\\boxed{\bf~x=-5}

 

 

7 0
3 years ago
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