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3 years ago

PLEASE HELP ASAP IT IS VERY MUCH APPRECIATED

Mathematics

2 answers:

irakobra [83]3 years ago

5 0

YOUR CORRECT good luckkk

Alika [10]3 years ago

3 0

Answer:

I think the answer is y= -2/x

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Anybody know this question

Dmitrij [34]

<h3>Answers :-</h3>

sinB = 12/13
cosB = 5/13
tanB = 12/5

Here as by the given information ,

♦ sinA = Opposite/Hypotenuse

♦ cosA = Adjacent/Hypotenuse

♦ TanA = Opposite/adjacent

So here we need to find the same for angle B so we need to use the same formulas for angle B also .

→ sinB = Opposite/Hypotenuse = 12/13

→ cosB = Adjacent/Hypotenuse = 5/13

→ tanB = Opposite/Adjacent = 12/5

8 0

3 years ago

Write 6 3/2 in surd form.

dolphi86 [110]

Answer:

$6\sqrt{6}$

Step-by-step explanation:

Simplify using $a\frac{n}{m} =\sqrt[m]{a^n} :\sqrt{6^3}$

Factor and rewrite the radicand in exponential form: $\sqrt{6^2 x 6}$

Rewrite the expression using $\sqrt[n]{ab} =\sqrt[n]{a}*\sqrt[n]{b} : \sqrt{6^2x\sqrt{6}$

Simplify the radical expression

$6\sqrt{6}$

6 0

2 years ago

Help desprate here.....

rjkz [21]

Answer:

B. 3

It says the answer is too short so im just typing random stuff

6 0

3 years ago

Read 2 more answers

Consider the quadratic function f(x)=−x^2+x+30

yaroslaw [1]

Answer:

The smallest xx-intercept is $x = -5$

The largest xx-intercept is $x = 6$

The yy-intercept is $y = 30$ .

Step-by-step explanation:

Given a quadratic function in the following format:

$f(x) = ax^{2} + bx + c = 0, a \neq 0$

The x-values of the x-intercepts are $x_{1}, x_{2}$ , given by the following formulas.

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

We have that:

$f(x) = -x^{2} + x + 30$

This is not in the format above. I will multiply by (-1), so we have:

$f(x) = x^{2} - x - 30$

So, $a = 1, b = -1, c = -30$

$\bigtriangleup = b^{2} - 4ac = (-1)^{2} - 4*(1)*(-30) = 1 + 120 = 121$

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) + \sqrt{121}}{2(1)} = \frac{12}{2} = 6$

$x_{2} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) - \sqrt{121}}{2(1)} = \frac{-10}{2} = -5$

This means that

The smallest xx-intercept is $x = -5$

The largest xx-intercept is $x = 6$

The y-intercept is the value of f(x) when x = 0. So

$f(x)=−x^{2}+x+30$

$f(0) = 30$

The yy-intercept is $y = 30$ .

5 0

3 years ago

Solve the proportion.<br><br> 2/x+3=5/x

xenn [34]

$\displaystyle\bf\\\frac{2}{x+3}=\frac{5}{x}\\\\5(x+3)=2x\\\\5x+15=2x\\\\5x-2x=-15\\\\3x=-15\\\\x=\frac{-15}{3}\\\\\boxed{\bf~x=-5}$

7 0

3 years ago