Let n = required random sample size.
Assume that the population standard deviation is known as σ.
Let m = sample mean.
At the 95% confidence level, the expected range is
(m - k(σ/√n), m + k(σ/√n))
where k = 1.96.
Therefore the error margin is 1.96(σ/√n).
Because the error margin is specified as 3% or 0.03, therefore
(1.96σ)/√n = 0.03
√n = (1.96σ)/0.03
n = 128.05σ²
This means that the sample size is about 128 times the population variance.
Answer:
Smallest sample size = 128.05σ², where σ = population standard deviation.
Answer:
The answer is below
Step-by-step explanation:
Let x represent the number of days that fluffy eats wet food in a week and y represents the number of days that fluffy eats dry food in a week.
Hence:
x + y = 7 (1)
Also, John wants to spend at most $9.00 on cat food each week. Hence:
1.5x + 0.75y ≤ 9 (2)
The list of possible points after solving graphically are:
(0,7), (6,0), (0,12) and (5, 2). If x,y > 0, then the point that satisfies the inequality is:
(5, 2) i.e. 5 wet food and 2 dry food
Answer:
She has approximately 3 pieces ( 2.625)
Step-by-step explanation:
To get the number of pieces, we need to divide the length of the wire by the individual length of the pieces.
To get the division done, it would be easier to convert what we have into improper fractions
For the piece of wire, the length which is 4 and 3/8 centimeters long will be 35/8 centimeters
while;
the individual length of each of the piece which is 1 and 2/3 centimeters long will be 5/3 centimeters
The number of pieces is thus 35/8 divided by 5/3 = 35/8 * 3/5 = 21/8 = 2.625 which is approximately 3 pieces
Answer:
he needs 24 cans
Step-by-step explanation:
162.4 - 28 = 134.4
134.4 divided by 56 = 2.4
2.4 * 10 = 24
