It’s unsolvable with out more context. What’s the rest of the problem.
Answer:
0.83193
Step-by-step explanation:
Probability of having the Rhesus (Rh) factor present in their blood; p = 0.3
Sample size; n = 5
We want to find the probability the probability that at least one does not have the Rh factor.
This will be;1 - P(X < 1)
This is a binomial probability distribution. Thus;
P(X = k) = C(n, k) × p^(k) × (1 - p)^(n - k)
P(X < 1) = P(X = 0)
Thus;
P(X = 0) = C(5, 0) × 0.3^(0) × (1 - 0.3)^(5 - 0)
P(X = 0) = 1 × 1 × 0.16807
P(X = 0) = 0.16807
Thus;
1 - P(X < 1) = 1 - 0.16807 = 0.83193
1: given 2: distributive property 3: multiplication property of equality 4: addition property of equality 5: division property of equality
60 children tickets and 190 adult tickets were sold.
<u>Step-by-step explanation:</u>
Let the no. of adult tickets sold be 'a'
Let the no. of children tickets sold be 'c'
Total tickets sold = 250
Cost of 1 children ticket = $2.5
Cost of 1 adult ticket = $4
Total money collected= $910
Given that,
a + c = 250
a = 250 - c
4a + 2.5c = 910
Substitute a value
4(250 - c) + 2.5c = 910
1000 - 4c + 2.5c = 910
1000 - 1.5c = 910
-1. 5c = -90
1.5c = 90
c = 90/1.5
c = 60
a + c = 250
a + 60 = 250
a = 190
60 children tickets and 190 adult tickets were sold.
, we have
