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Scrat [10]
3 years ago
15

Mr. Schordine wants to fill up enough helium balloons to allow him to fly through the skies. He weighs 84 kilograms. He knows th

at every cubic meter of helium is able to lift about 1 kilogram, and the package for the balloons that he bought says that every balloon can be inflated to a sphere with a radius of 0.4 meters. How many balloons would it take to fulfill Mr. Schordine’s dream of flight?
Mathematics
1 answer:
Cerrena [4.2K]3 years ago
6 0

Answer:

There is needed around 311 balloons to fulfill Mr. Schordine’s dream of flight.

Step-by-step explanation:

First, we need to calculate the volume of each balloon by considering the balloons as a sphere:    

V = \frac{4}{3}\pi r^{3}

Where:

r: is the radius = 0.4 meters

V = \frac{4}{3}\pi r^{3} = \frac{4}{3}\pi (0.4 m)^{3} = 0.27 m^{3}

Knowing that 1 m³ of helium is able to lift about 1 kg, that Mr. Schordine weights 84 kg, and that each ballon has 0.27 m³ of helium, the number of balloons needed are:

N = \frac{1 m^{3}}{1 kg}*84 kg*\frac{1 balloon}{0.27 m^{3}} = 311.1 \: balloon              

Therefore, there is needed around 311 balloons to fulfill Mr. Schordine’s dream of flight.      

 

I hope it helps you!

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malfutka [58]

Answer:

Stephen: £36

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Step-by-step explanation:

2+2+1= 5

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3 years ago
Find the fifth term of a sequence whose first term is 8 and common ratio is 3/2
Arlecino [84]

Answer:

Option c. 81/2

Step-by-step explanation:

Fifth term: a5=?

First term: a1=8

Common ratio: r=3/2

an=a1*r^(n-1)

with n=5

a5=a1*r^(5-1)

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Replacing the known values:

a5=8*(3/2)^4

a5=8*(3)^4/(2)^4

a5=8*81/16

Simplifying: Dividing the numerator and denominator by 8:

a5=(8*81/8)/(16/8)

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3 years ago
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Answer:

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