Question

3. Suppose a free-fall ride at an amusement park starts at rest and is in free fall.

Answer 1

Answer:

$v = 22.54m/s$ --- Velocity

$h = 25.921m$ --- Distance

Explanation:

Given

$u = 0m/s$ --- Initial velocity

Solving (a): Velocity after 2.3s

To do this, we use the first equation of motion

$v = u + at$

Where

$t = 2.3s$

$a = g = 9.8m/s^2$

So, the equation becomes:

$v = 0 + 9.8 * 2.3$

$v = 0 + 22.54$

$v = 22.54m/s$

Solving (b): Distance covered in 2.3s

We make use of:

$h = ut + \frac{1}{2}gt^2$

This gives:

$h = 0 * 2.3 + \frac{1}{2}*9.8 * 2.3^2$

$h = \frac{1}{2}*9.8 * 5.29$

$h = 25.921m$