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3 years ago

During nuclear fission and fusion, matter that seems to disappear is actually converted into

Physics

2 answers:

iris [78.8K]3 years ago

8 0

Answer:

Energy (I need one more brainlist can i has?)

Explanation:

- Nuclear fusion occurs when two light nuclei fuse together into a heavier nucleus

- Nuclear fission occurs when a heavy, unstable nucleus breaks apart into two or more lighter nuclei

In both processes, the mass of the products is always smaller than the mass of the initial nuclei. This means that part of the initial mass has been converted into something else: into energy, which is released in the process.

The amount of energy released in the process can be calculated by using the famous Einstein's equivalence:

where m is the difference between the mass of the product and the initial mass of the nuclei, and c is the speed of light.

LenKa [72]3 years ago

6 0

Answer:

Energy

Explanation:

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A 250 kg crate is placed on an adjustable inclined plane. If the crate slides down the incline with an acceleration of 0.7 m/s2

stepladder [879]

Answer:

21.2 degrees

Explanation:

Let gravitational acceleration constant g = 9.81 m/s2 directed downward. We can calculate the g component that is parallel to the 25 degree incline:

$gsin25^0 = 9.81sin25^0 = 4.15 m/s^2$

This parallel component would produce an acceleration of the block. But since the net acceleration is only 0.7 m/s2, there's a friction acceleration that hinders g parallel. This acceleration can be calculated by

$4.15 - a_f = a = 0.7$

$a_f = 4.15 - 0.7 = 3.45 m/s^2$

The force of friction would be

$F_f = a_fm = 250 * 3.45 = 816.5 N$

Friction is a product of normal force and its coefficient

$F_f = \mu N = \mu mgcos25^0 = \mu 250*9.81*cos25^0 = 2222.72 \mu$

$\mu = F / 2222.72 = 816.5 / 2222.72 = 0.388$

For the crate to slide down at constant speed, the net acceleration must be 0. In other words, the parallel g must be the same as acceleration caused by friction. Let this incline angle be α

$g sin\alpha = a_f = F_f/m = \frac{\mu N}{m} = \frac{\mu mgcos\alpha}{m} = \mu g cos\alpha$

$sin\alpha = \mu cos\alpha$

$\frac{sin \alpha}{cos \alpha} = \mu$

$tan\alpha = \mu = 0.388$

$\alpha = tan^{-1} 0.388 = 0.37 rad = 0.37*180/\pi \approx 21.2^0$

6 0

4 years ago

A gas has an initial volume of 212 cm3 at a temperature of 293 K and a pressure of 0.98 atm. What is the final pressure of the g

Marizza181 [45]

Using the pressure law (P1 x V1)/ T1 = (P2 x V2)/ T2 where P1= the initial pressure V1= initial volume T1= initial temperature and P2= the final pressure V2= the final volume T2 = the final temperature and temperature is always in kelvin

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4 years ago

What happens in terms of energy when a moving car hits a parked car, causing the parked car to move?

adelina 88 [10]

that for every action there is an equal and opposite reaction. This means that forces happen in pairs for every interaction there is an object that causes the force and an object that is affected by it. So newtons 3rd law I would say.

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4 years ago

Does air pressure increase or decrease with an increase in altitude is the rate of change constant

Sliva [168]

The rate of pressure decreases with an increase in altitude is not constant. Rather, pressure decreases rapidly near Earth's surface and more gradually at greater heights.

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4 years ago

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BigorU [14]

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