The points (0,4) and (1, 9) fall on a particular line. What is its equation in slope-intercept
1 answer:
Answer:
The equation is y = 5x + 4.
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Step-by-step explanation:
☆Remember:
☆Slope-intercept:
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☆We need to find the slope first. So just plug in according to the slope formula!
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☆Now we need to find the y-intercept. We are going to plug in the slope and a set of coordinates to find the y-intercept.
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☆Now all we need to do is plug in and we are done!
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Answer:
a. -⅓
b. 3
c. y = 3x - 10
Step-by-step explanation:
a. Gradient of line AB:
A(1, 3), B(7, 1)
Gradient (m) = -⅓
b. The of the line that is perpendicular to line AB would be the negative reciprocal of the gradient of line AB.
Thus, the negative reciprocal of -⅓ = 3
Gradient of the line perpendicular to line AB = 3
c. Equation of the line that passes through (4, 2) and is perpendicular to line AB:
We can write the equation using the point-slope form equation, y - b = m(x - a), where,
(a, b) represents a point on the line, and,
m = gradient/slope
We know that the gradient/slope (m) = 3
Also, a point, (a, b) = (4, 2).
Therefore, substitute a = 4, b = 2, and m = 3 into y - b = m(x - a)
Thus:
y - 2 = 3(x - 4)
y - 2 = 3x - 12
Add 2 to both sides
y = 3x - 12 + 2
y = 3x - 10