Pls pls pls pls help me

Alan is giving a basic math test in his class. One of the questions in the test is about finding two factors of the number 221.

NARA [144]

Answer:

★ The two factors of the number 221 are 13 and 17.

A factor refers to a whole number, which fits evenly into another whole number. Thus, factors are the numbers, which we multiply together to get another number. The two numbers that can be multiply together to get 221 are 13 and 17.

Step-by-step explanation:

Hope you have a great day :)

6 0

3 years ago

There are 150 people in the library. If 60 of them are girls, what percent of the people in the library are girls?

Irina18 [472]

Answer:

40% are girls

Step-by-step explanation:

60/150=0.4=40%

5 0

2 years ago

PLS HELP I ONLY HAVE UNTIL TOMORROW, I WILL GIVE BRAINLIEST TO WHO ANSWERS CORRECTLY AND EXPLAINS

-BARSIC- [3]

I’ve seen this exact question so many times from other people

7 0

3 years ago

A piece of wire 30 m long is cut into two pieces. One piece is bent into a square and the other is bent into a circle.

antiseptic1488 [7]

Answer:

a) 0 m

b) 16.8 m

Step-by-step explanation:

A piece of wire, 30 m long, is cut in two sections: a and b. Then, the relation between a and b is:

$a+b=30\\\\b=30-a$

The section "a" is used to make a square and the section "b" is used to make a circle.

The section "a" will be the perimeter of the square, so the square side will be:

$l=a/4$

Then, the area of the square is:

$A_s=l^2=(a/4)^2=a^2/16$

The section "b" will be the perimeter of the circle. Then, the radius of the circle will be:

$2\pi r=b=30-a\\\\r=\dfrac{30-a}{2\pi}$

The area of the circle will be:

$A_c=\pi r^2=\pi\left(\dfrac{30-a}{2\pi}\right)^2=\pi\left(\dfrac{900-60a+a^2}{4\pi^2}\right)=\dfrac{900-60a+a^2}{4\pi}$

The total area enclosed in this two figures is:

$A=A_s+A_c=\dfrac{a^2}{16}+\dfrac{900-60a+a^2}{4\pi}=\left(\dfrac{1}{16}+\dfrac{1}{4\pi}\right)a^2-\dfrac{60a}{4\pi}+\dfrac{900}{4\pi}$

To calculate the extreme values of the total area, we derive and equal to 0:

$\left(\dfrac{1}{16}+\dfrac{1}{4\pi}\right)a^2-\dfrac{60a}{4\pi}+\dfrac{900}{4\pi}\\\\\\\dfrac{dA}{da}=\left(\dfrac{1}{16}+\dfrac{1}{4\pi}\right)(2a)-\dfrac{60}{4\pi}+0=0\\\\\\\left(\dfrac{1}{8}+\dfrac{1}{2\pi}\right)a=\dfrac{15}{\pi}\\\\\\\dfrac{\pi+4}{8\pi}\cdot a=\dfrac{15}{\pi}\\\\\\\dfrac{\pi+4}{8}\cdot a=15\\\\\\a=15\cdot \dfrac{8}{\pi+4}\approx 16.8$

We obtain one value for the extreme value, that is a=16.8.

We can derive again and calculate the value of the second derivative at a=16.8 in order to know if the extreme value is a minimum (the second derivative has a positive value) or is a maximum (the second derivative has a negative value):

$\dfrac{d^2A}{da^2}=\left(\dfrac{1}{16}+\dfrac{1}{4\pi}\right)(2)-0=\dfrac{1}{8}+\dfrac{1}{2\pi}>0$

As the second derivative is positive at a=16.8, this value is a minimum.

In order to find the maximum area, we analyze the function. It is a parabola, which decreases until a=16.8, and then increases.

Then, the maximum value has to be at a=0 or a=30, that are the extremes of the range of valid solutions.

When a=0 (and therefore, b=30), all the wire is used for the circle, so the total area is a circle, which surface is:

$A=\pi r^2=\pi\left( \dfrac{30}{2\pi}\right)^2=\dfrac{900}{4\pi}\approx71.62$

When a=30, all the wire is used for the square, so the total area is:

$A=a^2/16=30^2/16=900/16=56.25$

The maximum value happens for a=0.

3 0

3 years ago

a 6 ounce package costs $2.10 a 16 ounce package costs $5.28 a 26 ounce package costs $9.36 which package is the best buy

Andru [333]

Answer:

The better buy is the 16 ounce package for $5.28.

Step-by-step explanation:

First divide each price with their ounce,so 2.10 ÷ 6 = 2.1 per 1 ounce , 5.28 ÷ 16 = 0.33 per 1 ounce , 9.35 ÷ 26 = 0.36 per 1 ounce.

Next compare the prices for 1 ounce and see which on is lower. The 16 ounce package has a better price because the price for each ounce is lower than the other prices.

6 0

3 years ago