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3 years ago

Solve for x in the inequality below. 4x-8<5x+4

Mathematics

2 answers:

zvonat [6]3 years ago

6 0

Answer:

-12 < x

Step-by-step explanation:

4x-8<5x+4

Subtract 4x from each side

4x-4x-8<5x-4x+4

-8 < x+4

Subtract 4 from each side

-8-4 < x+4-4

-12 < x

Eddi Din [679]3 years ago

3 0

Answer:

Step-by-step explanation:

4x-8<5x+4

4x<5x+12

-x<12

flip sign

x > -12

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Answer:

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Step-by-step explanation:

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3 years ago

(X^1/8 y^1/4 z^1/2)^8

adell [148]

(x^1/8 y^1/4 z^1/2)^8
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3 years ago

Compute the flux H F of F(x,y) = hxy, x − yi across the boundary of the square given by −1 ≤ x ≤ 1, −1 ≤ y ≤ 1.

Softa [21]

Answer:

4i.

Step-by-step explanation:

To find the flux through the square, we use the divergence theorem for the flux. So Flux of F(x,y) = ∫∫divF(x,y).dA

F(x,y) = hxy,x - yi

div(F(x,y)) = dF(x,y)/dx + dF(x,y)dy = dhxy/dx + d(x - yi)/dy = hy - i

So, ∫∫divF(x,y).dA = ∫∫(hy - i).dA

= ∫∫(hy - i).dxdy

= ∫∫hydxdy - ∫∫idxdy

Since we are integrating along the boundary of the square given by −1 ≤ x ≤ 1, −1 ≤ y ≤ 1, then

∫∫divF(x,y).dA = ∫₋₁¹∫₋₁¹hydxdy - ∫₋₁¹∫₋₁¹idxdy

= h∫₋₁¹{y²/2}¹₋₁dx - i∫₋₁¹[y]₋₁¹dx

= h∫₋₁¹{1²/2 - (-1)/2²}dx - i∫₋₁¹[1 - (-1)]dx

= h∫₋₁¹{1/2 - 1)/2}dx - i∫₋₁¹[1 + 1)]dx

= 0 - i∫₋₁¹2dx

= - 2i[x]₋₁¹

= 2i[1 - (-1)]

= 2i[1 + 1]

= 2i(2)

= 4i

7 0

3 years ago

Hello help me with this question thanks in advance

Ede4ka [16]

$\bold{\huge{\green{\underline{ Solutions }}}}$

<h3>Answer 11 :-</h3>

We have, 

$\sf{HM = 5 cm }$

In square all sides of squares are equal

The perimeter of square 

$\sf{ = 4 × side }$

$\sf{ = 4 × 5 }$

$\sf{ = 20 cm }$

Thus, The perimeter of square is 20 cm

Hence, Option C is correct .

<h3>Answer 12 :-</h3>

We have, 

$\sf{MX = 3.5 cm }$

In square, diagonals are equal and bisect each other at 90°

Here, 

$\sf{MX = MT/2}$

$\sf{MT = 2 * 3.5 }$

$\sf{MT = 7 cm}$

Thus, The MT is 7cm long

Hence, Option C is correct .

<h3>Answer 13 :- </h3>

We have to find the measure of Angle MAT

All angles of square are 90° each

From above

$\sf{\angle{MAT = 90° }}$

Thus, Angle MAT is 90°

Hence, Option B is correct .

<h3>Answer 14 :-</h3>

We know that, 

All the angles of square are equal and 90° each

Therefore, 

$\sf{\angle{MHA = }}{\sf{\angle{ MHT/2}}}$

$\sf{\angle{MHA = 90°/2}}$

$\sf{\angle {MHA = 45°}}$

Thus, Angle MHA is 45°

Hence, Option A is correct

<h3>Answer 15 :- </h3>

Refer the above attachment for solution

Hence, Option A is correct

<h3>Answer 16 :- </h3>

Both a and b

The median of isosceles trapezoid is parallel to the base
The diagonals are congruent

Hence, Option C is correct

<h3>Answer 17 :-</h3>

In rhombus PALM,

All sides and opposite angles are equal

Let O be the midpoint of Rhombus PALM

In ΔOLM, By using Angle sum property :-

$\sf{35° + 90° + }{\sf{\angle{ OLM = 180°}}}$

$\sf{\angle{OLM = 180° - 125°}}$

$\sf{\angle{ OLM = 55° }}$

Now, 

$\sf{\angle{OLM = }}{\sf{\angle{OLA}}}$

OL is the bisector of diagonal AM

Therefore, 

$\sf{\angle{ PLA = 55° }}$

Thus, Angle PLA is 55° .

Hence, Option C is correct

8 0

3 years ago

Suzanne ran 334 miles in the morning and 412 miles in the afternoon. How many kilometers did she run altogether? Assume 1 mile

morpeh [17]

1193.6 because 334+412=746 and 746*1.6=1193.6

8 0

3 years ago

Solve for x in the inequality below. 4x-8<5x+4​

Solve for x in the inequality below. 4x-8<5x+4