Slope/m=3-(-7)/-3-2=10/-5=-2
slope/m=-2
y=-2x+b
b= 3=-2*-3+b
b=-3
If the length, breadth and height of the box is denoted by a, b and h respectively, then V=a×b×h =32, and so h=32/ab. Now we have to maximize the surface area (lateral and the bottom) A = (2ah+2bh)+ab =2h(a+b)+ab = [64(a+b)/ab]+ab =64[(1/b)+(1/a)]+ab.
We treat A as a function of the variables and b and equating its partial derivatives with respect to a and b to 0. This gives {-64/(a^2)}+b=0, which means b=64/a^2. Since A(a,b) is symmetric in a and b, partial differentiation with respect to b gives a=64/b^2, ==>a=64[(a^2)/64}^2 =(a^4)/64. From this we get a=0 or a^3=64, which has the only real solution a=4. From the above relations or by symmetry, we get b=0 or b=4. For a=0 or b=0, the value of V is 0 and so are inadmissible. For a=4=b, we get h=32/ab =32/16 = 2.
Therefore the box has length and breadth as 4 ft each and a height of 2 ft.
The correct answer is A!
c(x) = 1.50 + 1.25x
Answer:
The measure of angle A' is 125°
Step-by-step explanation:
we know that
Under reflection, lengths, areas and angles do not change but orientation does
therefore
If angle A is 125°
then
after the reflection
m∠A=m∠A'
therefore
The measure of angle A' is 125°
Answer:
3/4
Step-by-step explanation:
since they already have a common denominator you'd add the numerators and keep the denominator. you'd get 6/8. Then you'd divide both the numerator and denominator by 2. 3/4 is your final answer.
