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sveta [45]
3 years ago
15

What’s is the gcf 33c,55cd

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
4 0
The GCF of 33c and 55cd is

33c/11c = 3
55cd/11c = 5d

the greatest common factor is 11c 

hope this helps
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What is the gcf of 120 and 220
yawa3891 [41]
The GCF of 120 and 220 Is 20 :)  Its is 20 because both numbers are divisional by 20 Hope this helped and thank u
6 0
3 years ago
Kitchen sets at a furniture store.
Alona [7]

Answer: yes

Step-by-step explanation:

4 0
3 years ago
Two brothers are sharing a certain sum of money in the ratio 2/3 : 3/5, if the largest share was Gh¢500.00. How much was shared
lina2011 [118]

Given:

Two brothers are sharing a certain sum of money in the ratio \dfrac{2}{3}:\dfrac{3}{5}.

The largest share was Gh¢500.00.

To find:

The total amount shared between them.

Solution:

It is given that, two brothers are sharing a certain sum of money in the ratio \dfrac{2}{3}:\dfrac{3}{5}.

First we need to make the denominators common.

Ratio=\dfrac{2\times 5}{3\times 5}:\dfrac{3\times 3}{5\times 3}

Ratio=\dfrac{10}{15}:\dfrac{9}{15}

Ratio=10:9

So, the two brothers are sharing a certain sum of money in the ratio 10:9.

Let the shares of two brothers are 10x and 9x respectively. So, the larger share is 10x.

It is given that the largest share was Gh¢500.00.

10x=500

x=\dfrac{500}{10}

x=50

Now, the total amount shared between them is:

Total=10x+9x

Total=19x

Total=19(50)

Total=950

Therefore, the total amount shared between them is Gh¢950.00.

5 0
2 years ago
Consider the equation 2x+1=16
Aliun [14]

Step-by-step explanation:

2x + 1 = 16

2x = 15 (subtract 1 on both sides)

x = 7.5 (divide 2 om both sides)

Since 7.5 is not an integer, (a) is No.

However 7.5 is rational, therefore (b) is Yes.

6 0
2 years ago
Read 2 more answers
Please help mee pleaseee
nalin [4]

Answer:

The exact answer in terms of radicals is x = 5*\sqrt[3]{25}

The approximate answer is x \approx 14.62009 (accurate to 5 decimal places)

===============================================

Work Shown:

Let y = \sqrt[5]{x^3}

So the equation reduces to  -7  = 8-3y

Let's solve for y

-7 = 8-3y

8-3y = -7

-3y = -7-8 ... subtract 8 from both sides

-3y = -15

y = -15/(-3) ... divide both sides by -3

y = 5

-----------

Since y = \sqrt[5]{x^3} and y = 5, this means we can equate the two expressions and solve for x

y = 5

\sqrt[5]{x^3} = 5

x^3 = 5^5 Raise both sides to the 5th power

x^3 = 3125

x = \sqrt[3]{3125} Apply cube root to both sides

x = \sqrt[3]{125*25}

x = \sqrt[3]{125}*\sqrt[3]{25}

x = \sqrt[3]{5^3}*\sqrt[3]{25}

x = 5*\sqrt[3]{25}

x \approx 14.62009

4 0
3 years ago
Read 2 more answers
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