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Flura [38]
2 years ago
9

When Carla looked out at the school parking lot, she noticed that for every 2 minivans, there were 5 other vehicles. If there ar

e 161 vehicles in the parking lot, how many of them are not minivans? please!!!!
Mathematics
2 answers:
Nookie1986 [14]2 years ago
6 0

Answer:

Step-by-step explanation:

Marina86 [1]2 years ago
6 0

Answer:

The number of minivans at the school parking is equal to  46

The number of other types of vehicles at the school parking is equal to  115

the answer is  115

The number of vehicles that are not minivans is 115

Step-by-step explanation:

You might be interested in
I want only question number 3
zmey [24]

Answer:

Computers R Us has a better price because it cost less at the same production rate.

Step-by-step explanation: to graph y=23.5x you just plug in numbers. If x = 1, 23.5 (1), which equals y. Now you can keep doing this to get up to 4. You may use a calculator if youd like.


3 0
3 years ago
Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

7 0
3 years ago
Which story problem is solved using multiplication? Answer options with 5 options
galina1969 [7]
D is the answer because it says each and that’s a key word to understand that it’s multiplying
5 0
3 years ago
Read 2 more answers
Mrs. Martz is travelling to 300 miles to Florida
Scrat [10]

Answer:

:)

Step-by-step explanation:

300/60%=180

5 0
3 years ago
It is estimated that approximately 8.26% Americans are afflicted with diabetes. Suppose that a certain diagnostic evaluation for
sweet [91]

Answer:

0.032109

Step-by-step explanation:

From the given information

the estimate of those afflicted with diabetes = 0.0826

the estimate of those that are not afflicted with diabetes = 1 - 0.0826

= 0.9174

From adult with 40

Pr (correct diagnoses) = 0.945

Pr(incorrect diagnoses) = 0.035

The objective that the probability of a randomly selected adult which is over 40 and does not have diabetes, and is diagnosed as having diabetes (false positive) is =  0.9174 × 0.035

= 0.032109

8 0
3 years ago
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