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Yuri [45]
3 years ago
14

the combustion of ethane (c 2 h 6 ) is represented by the equation: 2c 2 h 6 (g) 7o 2 (g) 4co 2 (g) 6h 2 o(l) in this reaction:

(a) the rate of consumption of ethane is seven times faster than the rate of consumption of oxygen. (b) the rate of formation of co 2 equals the rate of formation of water. (c) water is formed at a rate equal to two-thirds the rate of formation of co 2 . (d) the rate of consumption of oxygen equals the rate of consumption of water. (e) co 2 is formed twice as fast as ethane is consumed.
Chemistry
1 answer:
DedPeter [7]3 years ago
4 0

Answer:

(e) CO2 is formed twice as fast as ethane is consumed.

Explanation:

Since we have the equation of the reaction as;

2C2H6(g) + 7O2(g)  4CO2(g) + 6H2O(l)

The rate of consumption of ethene =  -1/2 d[C2H6]/dt

Rate of production of CO2= 1/4 d[CO2]/dt

Hence, CO2 is formed twice as fast as ethane is consumed.

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An organism from the past that is related to all the organisms in the group is called?​
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3 years ago
Compounds A and B react to give a single product, C. Write the rate law for each of the following cases and determine the units
emmasim [6.3K]

Answer:

Explanation:

Rate laws are mathematical expressions which define the relationship that exists between the rate of a chemical reaction and the concentration of the reacting components. Rate laws take the following form:

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5 0
3 years ago
What are five general properties of aqueous bases? b. Name some common substances that have one or more of these properties.
ella [17]

Answer:

Explanation:(1)base are slippery to touch e.g sodium hydroxide NaOH(aq)..

(2) They can be corrosive e.g pottasium hydroxide KOH(aq) and sodium hydroxide NOH(aq)

(3) They can act as electrolytes e.g NaOH(aq)

(4) they react to acids to form salt and water

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4 0
3 years ago
Read 2 more answers
4) In water, Vanillin, C8H8O3, has a solubility of 0.070 moles of vanillin per liter of solution at 25C. What will be produced i
jeka94

Answer:

An unsaturated solution.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to firstly realize we need to calculate the grams of vanillin in 0.070 moles by using its molar mass of 152.15 g/mol:

m=0.070mol*\frac{152.15 g}{1mol} =10.65g

Thus, since the solubility is 10.65 g per 1 L of solution, we can notice 5.00 g will complete dissolve and produce an unsaturated solution.

Best regards!

8 0
3 years ago
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