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olchik [2.2K]
3 years ago
14

4) In water, Vanillin, C8H8O3, has a solubility of 0.070 moles of vanillin per liter of solution at 25C. What will be produced i

f 5.00 g of vanillin are added to 1 L of water at 25 C
Chemistry
1 answer:
jeka943 years ago
8 0

Answer:

An unsaturated solution.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to firstly realize we need to calculate the grams of vanillin in 0.070 moles by using its molar mass of 152.15 g/mol:

m=0.070mol*\frac{152.15 g}{1mol} =10.65g

Thus, since the solubility is 10.65 g per 1 L of solution, we can notice 5.00 g will complete dissolve and produce an unsaturated solution.

Best regards!

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This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.

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Q=-40036+(-672.21)=-40708.21J

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Q=-40708.21J*\frac{1kJ}{1000J}\\\\Q=-40.7kJ

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