The element which is oxidized in the reaction below
that is
Fe(Co)5 (l) + 2 Hi (g)= Fe (CO)4 i2(s) +Co (g)+H2 (g) is
Fe this is because fe in Fe(CO)5 compound move from oxidation state of Positive five (5^+) to oxidation state of positive six ( 6^+) in Fe(CO)4i2 compound. fe is oxidized by Hi while Hi itself is reduced by Fe,therefore Fe act as a reducing agent
Answer:
lithium
Explanation:
this is because lithium has a valency of 1 and oxygen has a valency of 2 thereby exchanging valency to create Li²0
I’m pretty sure 8 as well because elctrouns can’t hold more than that
1. Berkelium(Berkeley, CA) 2. Dubnium(Dubna, Russia) 3. Darmstaditum (Darmstadt, Germany) 4. Erbium(Ytterby, Sweden) 5. Strontium(Strontian, Scotland) 6. Terbium(Ytterby, Sweden) 7. Yttebium(Ytterby, Sweden) 8. Yttrium(Ytterby, Sweden)
Nitrate
Hope this helps :))