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harkovskaia [24]
3 years ago
5

Find the least common multiple of 15[[m]^[3]] and 12[[b]^[2]] .

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
6 0

Answer:

60m³b²

Step-by-step explanation:

We need to find the least common multiple of 15 m³ and 12 b².

Prime factorization of 15 m³ = 3×5×m³

Prime factorization of 12 b² = 3×2×2×b²

Common = 3×5×m³×2×2×b²

= 60m³b²

So, the least common multiple of 15 m³ and 12 b² is equal to 60m³b².

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Find the missing measures. Write your numerical answers only with a comma in between.
Katen [24]

Answer:

m∠T = 72°

m∠U = 54°

Step-by-step explanation:

Property of an isosceles triangle,

Opposite angles of two equal sides of an isosceles triangle are equal in measure.

By this property, in the given triangle STU,

Since, ST ≅ TU,

m∠S = m∠U = 54°

Since, sum of interior angles of a triangle is 180°

m∠T + m∠S + m∠U = 180°

m∠T + 54° + 54° = 180°

m∠T = 180° - 108°

m∠T = 72°

7 0
3 years ago
At a large nursery, a border for a rectangular garden is being built. Designers want the border’s length to be twice as long as
sasho [114]

Let

x--------> the border’s length

y--------> the border’s width

P--------> perimeter of the border

we know that

x=5+y------> equation 1

P=2*[x+y]-----> P=2x+2y

P <=180 ft

(2x+2y) <= 180-------> equation 2

substitute the equation 1 in equation 2

2*[5+y]+2y <= 180

10+2y+2y <= 180

4y <= 180-10

4y <=170

y <=42.5 ft

so

the maximum value of the width is 42.5 ft

for y=42.5 ft

x=42.5+5------> x=47.5 ft

the answer is

the width of the border is less than or equal to 42.5 ft

7 0
3 years ago
Hdhdhdbsnsjidhdbendx
nlexa [21]

Answer:

hdhwvejrfgnwruge. love that . ask a question though id love to help!

Step-by-step explanation:

you got this buddy lol

5 0
3 years ago
Read 2 more answers
If i= the square root of -1 what is the value of i^3
BARSIC [14]

i =√-1

i^2 = -1

so

i^3

= i^2 * i

=  -1√-1

= - √-1

5 0
3 years ago
A random sample of 1141 men and 1212 women aged 25-64 y (response rate 76%) completed a questionnaire and underwent a short exam
Dennis_Churaev [7]

Answer:

(a) A cross sectional study (b) The parameter can be computed as follows: Non-drinkers who agree exposed to obesity, Drinkers who are exposed or vulnerable to obesity (c) A postie relationship is established from the experiment between drinkers who are exposed to obesity and non drinkers who are exposed to obesity

Step-by-step explanation:

(a) The type of design is refereed to as a cross sectional study

(b) Now, because 50 men are beer drinkers out of 891 men.

Hence we can deduce form this that  500/891 gives us 0.56%.

This suggest that 0.56% men are beer drinkers out of which 325 have obesity, lets take for example 235/500 = 0.65% are exposed to obesity in which 80/ (89-500) = 80/491 = 0.16%

The non drinkers are 0.16% and are not exposed to obesity

Thus,

The parameters to be calculated is stated below:

  • Non-drinkers who agree exposed to obesity
  • Drinkers who are exposed or vulnerable to obesity

(c) The next step is to determine and explain the results.

In this case we can say there is a positive relationship between drinkers and non drinkers, since from the experiment 0.65% are exposed to obesity and 0.16$ non drinkers are exposed to obesity.

8 0
3 years ago
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