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3 years ago

Find the least common multiple of 15[[m]^[3]] and 12[[b]^[2]] .

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

6 0

Answer:

60m³b²

Step-by-step explanation:

We need to find the least common multiple of 15 m³ and 12 b².

Prime factorization of 15 m³ = 3×5×m³

Prime factorization of 12 b² = 3×2×2×b²

Common = 3×5×m³×2×2×b²

= 60m³b²

So, the least common multiple of 15 m³ and 12 b² is equal to 60m³b².

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jolli1 [7]

Answer:

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Step-by-step explanation:

Assuming 2.04 x 10^11 was only a typo

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3 years ago

3(x-2)+2(x+1)=-14<br> plz show work

Rom4ik [11]

Hello!

First, let's write the problem.
$3\left(x-2\right)+2\left(x+1\right)=-14$
Apply the distributive property on the left side of the equation.
$=3x-6+2x+2$
Add like terms.
$=5x-4$
Let's plug that in into the original equation.
$5x-4=-14$
Add 4 to both sides.
$5x-4+4=-14+4$
$5x=-10$
Divide both sides by 5.
$\frac{5x}{5}=\frac{-10}{5}$

Our final answer would be,
$x=-2$

You can feel free to let me know if you have any questions regarding this!
Thanks!

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Answer:

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