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3 years ago

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Your class hopes to collect at least 325 cans of food for the annual food drive. there were 135 cans donated the first week and

89 more the second week.
A;write an inequality that describes this situation. let C represent the number of cans of food that must be collected by the end of the third week for your class to meet your surpass its goal.
B; how may cans are needed to meet or surpass the goal

1 answer:

vampirchik [111]3 years ago

5 0

They have collected $135+89=224$ cans until now. To equal 325, they need $325-224=101$ cans more.

A.

Let C be the number needed to equate atleast 325.

$135+89+C\geq 325$

B.

If we solve the inequality in part A, we can find minimum number of C to meet the goal of 325 cans.

$135+89+C\geq 325\\224+C\geq325\\C\geq325-224\\C\geq101$

<em>So they need minimum 101 to complete the target and more than that to surpass.</em>

ANSWER: 101 cans are needed to meet the goal and more than that to surpass the goal.

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