Question

Your class hopes to collect at least 325 cans of food for the annual food drive. there were 135 cans donated the first week and 89 more the second week.
A;write an inequality that describes this situation. let C represent the number of cans of food that must be collected by the end of the third week for your class to meet your surpass its goal.
B; how may cans are needed to meet or surpass the goal

Answer 1

They have collected $135+89=224$ cans until now. To equal 325, they need $325-224=101$ cans more.

A.

Let C be the number needed to equate atleast 325.

$135+89+C\geq 325$

B.

If we solve the inequality in part A, we can find minimum number of C to meet the goal of 325 cans.

$135+89+C\geq 325\\224+C\geq325\\C\geq325-224\\C\geq101$

So they need minimum 101 to complete the target and more than that to surpass.

ANSWER: 101 cans are needed to meet the goal and more than that to surpass the goal.