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3 years ago

7

Order these numbers from least to greatest. −270 , 16310 , −503 , −16.5

1 answer:

pychu [463]3 years ago

8 0

-503,-270,-16.5,16310

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A fair, twenty-faced die has $19$ of its faces numbered from $1$ through $19$ and has one blank face. another fair, twenty-faced

lawyer [7]

Represent 24 as a sum of two numbers, first number from first die and second number from second die.
24=19+5=18+6=17+7=16+8=14+10=13+11=12+12=11+13=10+14=9+15=8+16=7+17=6+18=5+19=4+20 (the sums 15+9 and 20+4 are absent, because there aren't numbers: 20 on the first die and number 9 on the second die). Totally, you receive 15 different representations of 24.
<span>The probability that the sum of the two numbers facing up will be 24 is
</span><span>
</span><span> $P= \frac{15}{20\cdot 20} = \frac{3}{80}$ (here $20\cdot 20$ means that you have 20 possibilities to roll first number or blank face on the first die and 20 possibilities to roll number or blank face on the second die).
</span>

8 0

3 years ago

(11-6)^2+6x2-(3+3)^2<br><br> A. 0<br><br> B. 1<br><br> C. 16<br><br> D. 26

Dahasolnce [82]

Answer: =1

Step-by-step explanation:

$\left(11-6\right)^2+6\cdot \:2-\left(3+3\right)^2$

$=5^2+6\cdot \:2-\left(3+3\right)^2$

$=5^2+6\cdot \:2-6^2$

$=25+6\cdot \:2-6^2$

$=25+6\cdot \:2-36$

$=25+12-36$

$=1$

3 0

2 years ago

After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i

Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume ( $V$ ) is calculated by:

$V = \frac{4\pi}{3}\cdot R^{3}$

Where $R$ is the radius of the tumor.

The percentage decrease in the volume of the tumor ( $\%V$ ) is expressed by:

$\%V = \frac{\Delta V}{V_{o}} \times 100\,\%$

Where:

$\Delta V$ - Absolute decrease in the volume of the tumor.

$V_{o}$ - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

$\Delta V = V_{o}-V_{f}$

$\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})$

The percentage decrease is finally simplified:

$\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%$

Given that $R_{o} = R$ and $R_{f} = 0.77\cdot R$ , the percentage decrease in the volume of tumor is:

$\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%$

$\%V = 54.34\,\%$

The volume of the tumor experimented a decrease of 54.34 percent.

5 0

3 years ago

Solve for c. −58c=20<br><br> A-34<br> B-32<br> C26<br> D28

Dominik [7]

The answer is A: -34.

8 0

3 years ago

EASY 7TH GRADE MATH, WILL GIVE BRAINLIEST AND THANKS

Fudgin [204]

Answer:

D. 8

Step-by-step explanation:

2p=16

divide both sides by 2 to get p alone

p=8

7 0

3 years ago

Read 2 more answers