Answer:
$y=(7/2)x+20$
Step-by-step explanation:
SInce the gradient of the first line is $-2/7$ then the gradien of the perpendicular line is $7/2$.
Therefore by the point slope formula the line that we are looking for is
$y-6=(7/2)(x+4)$
$y=(7/2)x + 20$
The total revenue of the function is the product of the quantity and the price
The total revenue in terms of P is TR = 20P - 0.01P^2
<h3>How to determine the total revenue?</h3>
The demand and the cost functions are given as:
Quantity function, Q = 20 - 0.01P
Cost function, C(Q)=60+6Q
The total revenue is calculated as:
TR = Q * P
Substitute Q = 20 - 0.01P in the above equation
TR = P * [20 - 0.01P]
Evaluate the product
TR = 20P - 0.01P^2
Hence, the total revenue in terms of P is TR = 20P - 0.01P^2
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A customer borrowed $2000 and then a further $1000 both repayble in 12 months. What would he have saved if he had taken out one loan for $3000 repayable in 12 months?
He took two different loans, it charged him loan processing fee twice, two-time documentation process, and of course, extra time spent for second loan. Instead, he could take single loan of $3000 with one-time processing fee, one-time documentation process, and time-saving also.
The slope-intercept equation is y=mx+b.
The slope formula is 
Our three points are (5,5), (-5,-7) and (0,-1)
Using our slope formula our slope becomes 
Then, if we use one of our points (pick whichever you want, although (0,1) is the easiest) to solve the equation. So,
. When we solve for x and y, we get -1=0+b, or b=-1.
When we plug that back into the equation, we get
.