Answer:
C) 70%
Step-by-step explanation:
To find his percentage we take part over total
14/20
We want it over 100, so multiply the top and bottom by 5
14*5
---------
20*5
70/100
Percent means out of 100
so we have 70 percent
70 %
it would be 315. The simplest way to doing this would be by, first , doubling the number to make 252 which would add up to be 80%, and then divide 126 by 2 to get 63 which would be 20% ad by adding them all together you would get 315, which is equal to 100%.
Option C:
Area of the wall
square feet
Solution:
Length of the wall =
feet
Width of the wall =
feet
Area of the wall = length × width
Convert mixed fraction into improper fraction.
![$=\frac{12 \times 4+1}{4}\times \frac{7\times 4+3}{4}](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B12%20%5Ctimes%204%2B1%7D%7B4%7D%5Ctimes%20%20%5Cfrac%7B7%5Ctimes%204%2B3%7D%7B4%7D)
![$=\frac{49}{4}\times \frac{31}{4}](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B49%7D%7B4%7D%5Ctimes%20%20%5Cfrac%7B31%7D%7B4%7D)
![$=\frac{1519}{16}](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B1519%7D%7B16%7D)
Convert improper fraction into mixed fraction.
![$=94\frac{15}{16}](https://tex.z-dn.net/?f=%24%3D94%5Cfrac%7B15%7D%7B16%7D)
Area of the wall
square feet
Option C is the correct answer.
Answer:
![4x^3-7x^2-23x-10](https://tex.z-dn.net/?f=4x%5E3-7x%5E2-23x-10)
Step-by-step explanation:
So we have the expression:
![(4x+5)(x^2-3x-2)](https://tex.z-dn.net/?f=%284x%2B5%29%28x%5E2-3x-2%29)
Distribute. Multiply (4x+5) to each term:
![(x^2)(4x+5)+(-3x)(4x+5)+(-2)(4x+5)](https://tex.z-dn.net/?f=%28x%5E2%29%284x%2B5%29%2B%28-3x%29%284x%2B5%29%2B%28-2%29%284x%2B5%29)
Distribute:
![=(4x^3+5x^2)+(-12x^2-15x)+(-8x-10)](https://tex.z-dn.net/?f=%3D%284x%5E3%2B5x%5E2%29%2B%28-12x%5E2-15x%29%2B%28-8x-10%29)
Combine like terms:
![=(4x^3)+(5x^2-12x^2)+(-15x-8x)+(-10)](https://tex.z-dn.net/?f=%3D%284x%5E3%29%2B%285x%5E2-12x%5E2%29%2B%28-15x-8x%29%2B%28-10%29)
Add and simplify:
![=4x^3-7x^2-23x-10](https://tex.z-dn.net/?f=%3D4x%5E3-7x%5E2-23x-10)
And this is in descending order, so it's in standard form.