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tigry1 [53]
3 years ago
5

The problem is in the picture

Mathematics
1 answer:
Nitella [24]3 years ago
7 0
The problem is the number by the side
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Student loan: A student takes out an emergency loan for tuition, books, and supplies. The loan is for $200 with an interest rate
guapka [62]

Answer:

The answer is 120

Step-by-step explanation:

8 0
3 years ago
Please help I if you can thank you do much
strojnjashka [21]

Answer:

A. (Pay as you go) $120 B. (Regular deal) $90 C. (All-in-one price!) $100 D. The "Regular deal" option would be the least expensive for Carl.

Step-by-step explanation:

If Carl does the "Pay as you go" option he would be charged $6 each time. If he works out 20 times a month, we can multiply 20 by 6 to get a total of $120 for that option.

If Carl does the "Regular deal" option he would be charged $50 + an additional $2 for each time he works out. From there, we can get the equation 2x + 50 where x is the amount of time he works out. If we plug in 20 for x (as he works out 20 times a month), we get 2(20) + 50 which equals a total of $90 for that option.

If Carl does the "All-in-one Price!" option he would be charged $100 for the whole month meaning he has unlimited use of the gym with no extra charge besides the $100.

The cheapest option is the "Regular deal" option as it charges $90 compared to the $100 for the "All-in-one Price!" option & the $120 for the "Pay as you go" option.

7 0
3 years ago
I need help. I do not know if I am wrong or right.
kotykmax [81]

Answer:

I think you are correct

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which is the correct representation of the number –3.2 on a number line?
likoan [24]
I would say D i am not sure

4 0
3 years ago
Read 2 more answers
Suppose that, in addition to edge capacities, a flow network has vertex capacities. That is each vertex has a limit l./ on how m
storchak [24]

Answer:

See explanation and answer below.

Step-by-step explanation:

The tranformation

For this case we need to construct G' dividing making a division for each vertex v of G into 3 edges that on this case are v_1, v_2 and l(v).

We assume that the edges from the begin are the incoming edges of v_1 and all the outgoing edges from v are outgoing edges from v_2

We need to construct G' = (V', E') with capacity function a' and we need to satisfy the follwoing:

For every v \in V we create 2 vertices v_1, v_2 \in V'

Now we can add a new edge asscoiated to v_1, v_2 \in E' with the condition a' (v_1,v_2) = l(v)

Now for each edges (u,v)\in E we can create the following edge ( u_r, v_1) \in E' and the capacity is given by: a' (u_r, v_1) = a (u,v)

And for this case we can see this:

|V'| = 2|V|, |E'|= |E| +|V|

Now we assume that x is the flow who belongs to G respect vertex capabilities. We can create a flow function x' who belongs to G' with the following steps:

For every edge (u,v) \in G we can assume that x' (u_r ,v_1) = x(u,v)

Then for each vertex u \in V -t and we can define x\(u_1,u_r) = \sum_{v \in V} x(u,v) and x' (t_1,t_2) = \sum_{v \in V} x(v,t)

And after see that the capacity constraint on this case would be satisfied since for every edge in G' on the form (u_r, u_1) we have a corresponding edge in G because:

u \in V -(s,t) we have that:

x' (u_1, u_r) = \sum_{v \in V} x(u,v) \leq l(u) = a' (u_1, u_r)

x' (t_1,t_2) = \sum_{v \in V} x(v,t) \leq (t) = a' (t_1,t_2)

And with this we have the maximization problem solved.  

We assume that we have K vertices using the max scale algorithm.

6 0
3 years ago
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