To find the x int, sub in 0 for y and solve for x
4x - 3y = -24
4x - 3(0) = -24
4x = -24
x = -24/4
x = -6 <== ur x int...or (-6,0)
Answer: C
Step-by-step explanation:
If we know the value of the car decreases $500 for every 1,000 miles, and that the car is driven about 10,000 miles every year, that means that you need to take the total value of the car (23,000) and subtract it from the amount of money it is losing per year. Again, the car is driven about 10,000 miles per year, so that means that the car will most likely continue to be driven 10,000 miles per year. If you do the math, for one year, the value of the car will drop $5,000 ($500 x 10, because it is $500 per every 1,000 miles) So, for each year, you can just multiply the number of years by $5,000 to find out how much the vehicle has depreciated over time.
Hope this helped you and made sense! Feel free to ask me any questions you have!
Answer:
Mean is 12.13 months
Standard deviation is 1.29
Step-by-step explanation:
We need to use z-score here
Let the mean of the distribution be a while the standard deviation be b
Mathematically;
z-score = (x-mean)/SD
We can obtain the probability from the z-score
Now, for the 10th month
The z-score for a probability of P = 0.05(5%)
Can be obtained from the standard normal distribution table and that is;
-1.645
Hence;
-1.645 = (10 - a)/b
-1.645 b = 10 - a
a = 10 + 1.645b ••••••(i)
For the 13 month, we have a proportion of 75%
The z-score corresponding to P(0.75) is = 0.674 from standard normal distribution table
Hence;
0.674 = (13-a)/b
0.674b = 13 - a
a = 13 - 0.674b. •••••(ii)
Now equate both a;
10 + 1.645b = 13 - 0.674b
13-10 = 1.645 b+ 0.674b
3 = 2.319b
b = 3/2.319
b = 1.294
So the mean a will be
10 + 1.645b = 10 + 1.645(1.294) = 10 + 2.13
So mean is 12.13
Work shown above! Answer would be 110 degrees!
Answer:
False, the dilation factor is 2.
Step-by-step explanation:
Notice how each measure of the segments for the red quadrilateral is 2x the amount of the segments for the blue triangle? That right there is the dilation factor.
