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miv72 [106K]
3 years ago
11

The canoe costs $96 for 8 hours. How much does it cost per hour?

Mathematics
2 answers:
sergiy2304 [10]3 years ago
7 0

Answer: 12

96/8=12

12 is the unit rate per hour

vesna_86 [32]3 years ago
4 0

Answer:

$12

Step-by-step explanation:

just divide 96÷8=12

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Find the area of cross section,the lateral surface area,the total surface area and volume of the following prisms.​
FinnZ [79.3K]

Answer:

don't

Step-by-step explanation:

please send me only

7 0
3 years ago
Which expression is equivalent to (2^5)^-2
irinina [24]

<u><em>1/1024 is the correct answer.</em></u> First you had to apply exponent rule, and it gave us, \frac{1}{(2^5)^2}, or 2^5^*^2. Then you can also refine, and it gave us, 2^10, or \frac{1}{2^10}. And it gave us the answer is 2^1^0=2*2*2*2*2*2*2*2*2*2=1024, or 1/1024 is the correct answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

4 0
3 years ago
A rectangular pyramid has a height of 8 meters. The base is 7 meters in length and 15 meters in width two different triangular c
vagabundo [1.1K]

Answer:

The difference in the areas of the cross section is 32 m²

Step-by-step explanation:

The given parameters are;

The height of the rectangular pyramid = 8 meters

The length of the base of the pyramid = 7 meters

The width of the base of the pyramid = 15 meters

Whereby triangular cross sections are formed through the vertex and perpendicular to the base, and to each other, we have;

The sides of the two triangles consists of the following;

1) Two slant height of the pyramid each

2) The two perpendicular lines joining the midpoints of the opposite sides of the base of the pyramid with length equal to the length of the adjacent side to the sides from which they are drawn which are 15 meters and 7 meters

3) The two lines and the corresponding slant height form triangles cross section which are perpendicular to each other.

the slant height, h_l, is given as follows;

h_l = √(8² + (15/2)²) ≈ 10.966

For the triangular cross section with base = 15 m

The area of the cross section = 1/2 × Base₁₅ × Height = 1/2 × 15 m × 8 m = 60 m²

For the triangular cross section with base = 7 m

The area of the cross section = 1/2 × Base₇ × Height = 1/2 × 7 m × 8 m = 28 m²

The difference in the areas of the cross section = 60 m² - 28 m² = 32 m².

5 0
3 years ago
PLEASE HELP ME IM STRUGGLING!!!
Kitty [74]

Answer:

The required answer is c=7\sqrt{3}

Therefore the number in green box should be 7.

Step-by-step explanation:

Given:

AB = 7√2

AD = a , BD = b , DC = c , AC = d

∠B = 45°, ∠C = 30°

To Find:

c = ?

Solution:

In Right Angle Triangle ABD Sine identity we have

\sin B = \dfrac{\textrm{side opposite to angle B}}{Hypotenuse}\\

Substituting the values we get

\sin 45 = \dfrac{AD}{AB}= \dfrac{a}{7\sqrt{2}}

\dfrac{1}{\sqrt{2}}= \dfrac{a}{7\sqrt{2}}\\\\\therefore a=7

Now in Triangle ADC Tangent identity we have

\tan C = \dfrac{\textrm{side opposite to angle C}}{\textrm{side adjacent to angle C}}

Substituting the values we get

\tan 30 = \dfrac{AD}{DC}= \dfrac{a}{c}\\\\\dfrac{1}{\sqrt{3}}=\dfrac{7}{c}\\\\\therefore c=7\sqrt{3}

The required answer is c=7\sqrt{3}

8 0
3 years ago
given the following information about two loaded die, what is the p(5) on die 2? die 1p(1) = 0.5 p(4) = 0.25 p(6) = 0.25 die 2p(
bagirrra123 [75]

Answer:

0.45

Step-by-step explanation:

Die 1 is loaded so that only 1, 4, and 6 are possible.

P(1) + P(4) + P(6) = 0.5 + 0.25 + 0.25 = 1

Similarly, Die 2 is loaded so that only 2, 3, and 5 are possible.

P(2) + P(3) + P(5) = 1

0.3 + 0.25 + P(5) = 1

P(5) = 0.45

3 0
3 years ago
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