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Chetan has an average of 77on his first 3 math tests. He wants an average of 80. What equation can be used to find s, the score

Vikentia [17]

The answer is 89 percent because (80-77)x3=9 so 89

3 0

3 years ago

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Each container has a base of 4 1/4 yds by 1 2/3 yds. What is the area covered by all the containers?

svet-max [94.6K]

Answer:

See Explanation

Step-by-step explanation:

Given

Base Dimension

$Length = 4\frac{1}{4}yd$

$Width = 1\frac{2}{3}yd$

Required

The base area of all containers

First, calculate the base area of 1 container.

This is calculated as:

$Area = Length * Width$

$Area = 4\frac{1}{4}yd * 1\frac{2}{3}yd$

Express as improper fraction

$Area = \frac{17}{4}yd * \frac{5}{3}yd$

So, we have:

$Area = \frac{17*5}{4*3}yd^2$

$Area = \frac{85}{12}yd^2$

The number of containers is not given. So, I will use 'n' as the number of containers.

So, we have:

$Total = n * Area$

$Total= n * \frac{85}{12}yd^2$

--------------------------------------------------------------------------------------------

Assume n is 3 (i.e. 3 containers)

The total area is:

$Total= 3 * \frac{85}{12}yd^2$

$Total= \frac{85}{4}yd^2$

$Total= 21\frac{1}{4}yd^2$

--------------------------------------------------------------------------------------------

6 0

3 years ago

What’s the average of the following set of numbers ( 7,5,4,9)

Eduardwww [97]

Answer:

$6.25$

Step-by-step explanation:

$We\ are\ given:\\Observations\ in\ the\ Set=(7,5,4,9)\\ As\ we\ know\ that,\\ Average\ or\ interchangeably\ mean=\frac{Total\ Sum\ of\ observations }{Total\ no.\ of\ observations} \\Here,\\Total\ sum\ of\ the\ observations=7+5+4+9=25\\Total\ number\ of\ observations=4\\Hence\ here,\\Mean/Average=\frac{25}{4}=6.25$

6 0

3 years ago

another rectangle has length and width in the ratio of 3:2. If the length is increased by eight and the width is increased by 50

Andreyy89

Answer:

Area of the new rectangle = 148.8 cm square

Step-by-step explanation:

Let x be the dimensions of the rectangle then the

Perimeter of the Original rectangle= 2(L+B)

= 2 ( 3x+2x) = 2(5x)= 10xcm

If the length is increased by eight the new length would be 3x+ 8

and width would be 2x+x= 3x after 50 % increase

Perimeter of the new rectangle= 2(L+B)

= 2 ( 3x+8 +3x)

= 2 (6x+8)

= 12x + 16

Ratio of the new perimeter to the original perimeter is

New perimeter : Original perimeter

8 : 5

12x+ 16 : 10x cm

80x= 60x + 16

20x= 16

x= 16/20= 4/5

Putting the value of length and breadth in place of x

Area of the new rectangle = L*B = 3 * (4/5) +8 *3(4/5)=

= 12+ 40/5 * 12/5

= 62/5* 12/5

= 744/5

= 148.8 cm square

8 0

3 years ago

Please help :) this is exponential decay 10 pts

VMariaS [17]

$50.00 after 0 months and $37.50 after 6 months.
We first must calculate half-life using the attached formula.
Half-Life = (time * ln(2)) / ln (beginning amount/ending amount)
Half-Life = (6 * 0.69314718056) / ln (50.00 / 37.50)
Half-Life = ( 4.1588830834 ) / ln ( 1.3333333333 )
Half-Life = ( 4.1588830834 ) / 0.28768207245
Half-Life = 14.456525038 months

Now we need to calculate "lambda"
lambda = ln(2) / half-life
lambda = 0.69314718056 / 14.456525038
lambda = 0.0479470121 

Next we have to use this formula:
Ending Amount = beginning amount • e^( -lambda • time )
(where "e" is the mathematical constant 2.718281828...)
Ending Amount = 50 * 2.718281828^(-0.0479470121*24 months)
Ending Amount = 50 * 2.718281828^(-1.1507282904)
Ending Amount = 50 * 0.3164062499 
Ending Amount = 15.82 dollars

**********************************************************************
As a DOUBLE-CHECK we can work this out every 6 months:

0 months $50
6 months = $50 - (50 *.25) = 37.50
12 months = $37.50 -(37.50 *.25) = 28.125
18 months = $28.125 -(28.125 * .25) = 21.09375 
24 months = $21.09375 -(21.09375 * .25) = 15.8203125 

You'll find this page quite helpful:
http://www.1728.org/halflif2.htm

5 0

3 years ago

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