Question

Robert owns a doggy hotel. This is like a kennel but much fancier. Last friday the 14th he had 35 dogs that ate 3/8 of a pound of food. On friday the 7th he had 27 dogs that ate 1/2 of a pound each. which friday did he need more food and how many more pounds

Answer 1

Answer:

the 7th

0.007805 or  59 / 756

Step-by-step explanation:

To determine the Friday that he needed more pounds, determine the number of pounds he needed per dog for each Friday.

to do this, divide the total pounds by the number of dogs

on the 14th

3/8 ÷ 35 =

3/8 x 1/35 = 3/280

on the 7th

1/2 ÷ 27 =

1/2 x 1/27 = 1/54

to determine which fraction is larger multiply each by 100 to determine its percent

3/280 x 100 = 1.071

1/54 x 100 = 1.852

1/54 is larger. Thus, more pounds was needed on Friday the 7th

the difference between these fractions should be determined  

$\frac{1}{54}$ - $\frac{3}{280}$

$\frac{280 - 162}{1512}$ = $\frac{118}{1512}$ = 59 / 756