1. Ans: Option (B) 
Explanation:
Given:

Take the common out:
=>

Hence: =>
![[tex]-6x^4](https://tex.z-dn.net/?f=%5Btex%5D-6x%5E4)
[/tex] (Option B)
2. Ans: Option (D) 
Explanation:
Given:

Take the common term(s) out:
=>

Hence: =>

(Option D)
3. Ans: Option (B) 
<span>
quadratic trinomial
Explanation:
</span>Given:

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.
=> 
=>

(Option B)
4. Ans: Option (C) 
Explanation:
In order to find the total number of C<span>ommon and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:
</span>Common guppies:

<span>
Endler's guppies: </span>

(add both)
-----------------------------------------------------------------
Total number:

-----------------------------------------------------------------
Hence the ans is Option(C)
5. Ans: Option (D) 
Explanation:
First let's find the total area of the yard:
Total Area of the
Yard = 14x * 19x =

Now the area of the circular fountain:
Area of the Circular Fountain =

Since, r=6x
Therefore,
Area of the Circular Fountain =

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard =

-

=> Final area of the Yard =

(Option D)
6. Ans: Option (A) 
Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x =

Now the area of the stadium:
Area of the stadium = 1x * 4x =

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot=

-

=> Final area of the lot =

(Option A)
-i