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pychu [463]
3 years ago
12

PLease help me in this work!!!

Mathematics
2 answers:
Zinaida [17]3 years ago
8 0

Answer:

the first one is the expression

Sveta_85 [38]3 years ago
6 0
The second one
x-3x+4
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The answer to this difficult question in my math book that I have to solve. Can you help me?
s2008m [1.1K]
A half hour is 30 minutes. So you would need to divide 30 by 5 and you get six. Multiple 6 degrees Fahrenheit by 6 and you get 36 degrees. The solution cooled 36 degrees in half an hour.

Hope this helps!
4 0
3 years ago
A small submarine starts at –1,080 feet in relation to sea level. Then it descends 8 feet per minute for 11 minutes. What expres
BARSIC [14]

Answer:

-1,080 + (-8)(11)

Step-by-step explanation:Well for one it has to be -1,080 becuase it already starts as a neagtive. So the answer has to -1,080 + (-8)(11) becuase you adding/mutpilying  8 x 11

6 0
4 years ago
Average rate of change from x= 1 and x=2
iragen [17]

Answer:

What are the y values you can not find the average rate of change without the y values.

Step-by-step explanation:


5 0
3 years ago
Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Consider the
Dafna1 [17]

Answer:

a) \bar d= \frac{\sum_{i=1}^n d_i}{n}=72.2  

s_d =\sqrt{\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}} =9.311  

b) The 90% confidence interval would be given by (63.330;81.070)

63.330 < \mu_{left}- \mu_{right}  

Step-by-step explanation:

1) Previous concepts  and notation

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let put some notation  

x=left arm , y = right arm  

x: 175 169 182 146 144  

y: 102 101 94 79 79

The first step is define the difference d_i=x_i-y_i, that is given so we have:

d:  73, 68, 88, 67, 65

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}=72.2  

The third step would be calculate the standard deviation for the differences, and we got:  

s_d =\sqrt{\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}} =9.311  

2) Confidence interval

The confidence interval for the mean is given by the following formula:  

\bar d \pm t_{\alpha/2}\frac{s_d}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=5-1=4  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,4)".And we see that t_{\alpha/2}=2.13  

Now we have everything in order to replace into formula (1):  

72.2-2.13\frac{9.311}{\sqrt{5}}=63.330  

72.2+2.13\frac{9.311}{\sqrt{5}}=81.070  

So on this case the 90% confidence interval would be given by (63.330;81.070)

63.330 < \mu_{left}- \mu_{right}  

3 0
3 years ago
2² + 2[2(3+1)(3-2)-1]
laila [671]

Answer:

18

Step-by-step explanation:

hope this helps! :D

have a miraculous day!! <3

4 0
2 years ago
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