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pychu [463]
2 years ago
12

PLease help me in this work!!!

Mathematics
2 answers:
Zinaida [17]2 years ago
8 0

Answer:

the first one is the expression

Sveta_85 [38]2 years ago
6 0
The second one
x-3x+4
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Solve the inequality:<br>x+8 &gt; 14<br>O x26<br>O x2 22<br>Oxs 22<br>Ο κε 6​
almond37 [142]

Answer:

Option D, x > 6

Step-by-step explanation:

<u>Step 1:  Subtract 8 from both sides </u>

<u />x + 8 > 14

x + 8 - 8 > 14 - 8

x > 6

Answer:  Option D, x > 6

6 0
3 years ago
100 POINTS!!!!!! HELP
irga5000 [103]
A - 1766! I hope this helps
7 0
3 years ago
8. For circle A, the circumference is 31.4 ft. What is the area? Use 3.14 for pi
telo118 [61]

Answer:

\huge\boxed{\sf A = 78.5\ ft\²}

Step-by-step explanation:

Circumference = C = 31.4 ft

We know that,

<h3>C = 2πr</h3>

Where, r is the radius

31.4 = 2(3.14)r

31.4 = 6.28(r)

Divide 6.28 to both sides

31.4/6.28 = r

5 ft. = r

<h3>r = 5 ft.</h3>

Now,

<h3><u>Finding area:</u></h3>

A = πr²

A = (3.14)(5)²

A = (3.14)(25)

<h3>A = 78.5 ft²</h3>

\rule[225]{225}{2}

7 0
2 years ago
Read 2 more answers
Can you please help me
MariettaO [177]

Answer:

you will add the numerator and the denominator and or you look for lowest common factor

6 0
3 years ago
Find the unit tangent vector T(t) to the curve r(t) = [sin(t), 1 + t, cos(t)] when t = 0.
ss7ja [257]

Compute the derivative of \mathbf r(t) at t=0 - this will be the tangent vector - then normalize it by dividing it by its magnitude to get the unit tangent vector \mathbf T(t).

\mathbf r(t) = \langle \sin(t), 1+t, \cos(t) \rangle \implies \dfrac{d\mathbf r}{dt} = \langle \cos(t), 1, -\sin(t) \rangle \implies \dfrac{d\mathbf r}{dt}(0) = \langle 1, 1, 0 \rangle

\|\langle1,1,0\rangle\| = \sqrt{1^2+1^2+0^2} = \sqrt2

\implies\mathbf T(0) = \dfrac{\langle1,1,0\rangle}{\sqrt2} = \boxed{\left\langle \dfrac1{\sqrt2}, \dfrac1{\sqrt2}, 0\right\rangle}

7 0
1 year ago
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