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2 years ago

PLease help me in this work!!!

Mathematics

2 answers:

Zinaida [17]2 years ago

8 0

Answer:

the first one is the expression

Sveta_85 [38]2 years ago

6 0

The second one
x-3x+4

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Solve the inequality:<br>x+8 > 14<br>O x26<br>O x2 22<br>Oxs 22<br>Ο κε 6

almond37 [142]

Answer:

Option D, $x > 6$

Step-by-step explanation:

<u>Step 1: Subtract 8 from both sides </u>

<u /> $x + 8 > 14$

$x + 8 - 8 > 14 - 8$

$x > 6$

Answer: Option D, $x > 6$

6 0

3 years ago

100 POINTS!!!!!! HELP

irga5000 [103]

A - 1766! I hope this helps

7 0

3 years ago

8. For circle A, the circumference is 31.4 ft. What is the area? Use 3.14 for pi

telo118 [61]

Answer:

$\huge\boxed{\sf A = 78.5\ ft\²}$

Step-by-step explanation:

Circumference = C = 31.4 ft

We know that,

Where, r is the radius

31.4 = 2(3.14)r

31.4 = 6.28(r)

Divide 6.28 to both sides

31.4/6.28 = r

5 ft. = r

Now,

<h3><u>Finding area:</u></h3>

A = πr²

A = (3.14)(5)²

A = (3.14)(25)

$\rule[225]{225}{2}$

7 0

2 years ago

Read 2 more answers

Can you please help me

MariettaO [177]

Answer:

you will add the numerator and the denominator and or you look for lowest common factor

6 0

3 years ago

Find the unit tangent vector T(t) to the curve r(t) = [sin(t), 1 + t, cos(t)] when t = 0.

ss7ja [257]

Compute the derivative of $\mathbf r(t)$ at $t=0$ - this will be the tangent vector - then normalize it by dividing it by its magnitude to get the unit tangent vector $\mathbf T(t)$ .

$\mathbf r(t) = \langle \sin(t), 1+t, \cos(t) \rangle \implies \dfrac{d\mathbf r}{dt} = \langle \cos(t), 1, -\sin(t) \rangle \implies \dfrac{d\mathbf r}{dt}(0) = \langle 1, 1, 0 \rangle$

$\|\langle1,1,0\rangle\| = \sqrt{1^2+1^2+0^2} = \sqrt2$

$\implies\mathbf T(0) = \dfrac{\langle1,1,0\rangle}{\sqrt2} = \boxed{\left\langle \dfrac1{\sqrt2}, \dfrac1{\sqrt2}, 0\right\rangle}$

7 0

1 year ago