Answer:

Step-by-step explanation:
Given:
The terminal side of an angle in standard position passes through P(-3,-4).
- Point P is in Quadrant III
- In Quadrant |||,
is positive.

The result of multiplying the polynomials is (2x + 3) (-x + 2y - 4) = -2x² + 4xy - 11x + 6y - 12
<h3>How to multiply the
polynomials?</h3>
The polynomial expression is given as
(2x + 3) (-x + 2y - 4)
Expand the brackets in the above polynomial expression
So, we have
(2x + 3) (-x + 2y - 4) = 2x * (-x + 2y - 4) + 3 * (-x + 2y - 4)
Open the brackets in the above polynomial expression
So, we have
(2x + 3) (-x + 2y - 4) = -2x² + 4xy - 8x + -3x + 6y - 12
Evaluate the like terms in the above polynomial expression
So, we have
(2x + 3) (-x + 2y - 4) = -2x² + 4xy - 11x + 6y - 12
Hence, the solution is -2x² + 4xy - 11x + 6y - 12
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Answer:
The answer might be a 91% chance of her next throw
Step-by-step explanation:
Answer:
y = - 2x - 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = 
with (x₁, y₁ = (- 2, 2) and (x₂, y₂ ) = (1, - 4)
m =
=
= - 2, thus
y = - 2x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (- 2, 2), then
2 = 4 + c ⇒ c = 2 - 4 = - 2
y = - 2x - 2 ← equation of line
Answer:
angle R= 36.869
Step-by-step explanation:
CosR=8/10
cosR=0.8
R= inverse cos (0.8)
R=36.869